![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
The interval of the zero point of function f (x) = 2 to the power of X + 3x is () How to ask for such a? A-2 -1 B 0 1 C -1 0 D1 2
Now the zeros we are involved in are sign changing zeros, that is, the function values of the two endpoints of the interval where the zeros are located must be positive and negative, so we can find it. To do this question, just bring in the answer in turn. When the symbols of the two endpoints of the interval are different, that is, positive and negative, that option is the answer, so only item C of this question matches
What is the number of zeros of function f (x) = the third power of X - 2x square - x + 2?
f(x）=x^3-2x^2-x+2=x^2(x-2)-(x-2)=(x-2)(x^2-1)=(x-2)(x-1)(x+1)
Zero points are x = 2,1, - 1. There are 3 in total
The fourth power of X + the third power of 2x + the square of 3x + 2x + 1 Factorization Another question: the fourth power of X + the third power of 2x - the square of 9x - 2x + 8 (factorization)
1. Original formula x ^ 4 + 2x ^ 3 + 3x ^ 2 + 2x + 1
=x^4+2x^2+1+2x^3+x^2+2x
=(x^2+1)^2+x^3+x+x^3+x^2+x
=(x^2+1)^2+x(x^2+1)+x(x^2+x+1)
=(x^2+1)(x^2+x+1)+x(x^2+x+1)
=(x^2+1+x)(x^2+1+x)
=(x^2+1+x)^2
two
x^4+2x^3-9x^2-2x+8
=x^4+2x^3-x^2-2x+8-8x^2
=x^2(x^2-1)+2x(x^2-1)-8(x^2-1)
=(x^-1)(x^2+2x-8)
=(x+1)(x-1)(x+4)(x-2)
The square of negative x 2x is the third power of negative 3x and the fourth power of 4x The square of negative x 2x is the third power of negative 3x and the fourth power of 4x The law of coefficient sign? Absolute value law of coefficient? The law of frequency? Combined with the above, the nth monomial is?
The law of coefficient sign: odd term is positive and even term is negative
The law of absolute value of coefficient: increase successively from 1
The law of frequency: ibid
The nth monomial: a (n) = - 1 ^ n * NX ^ n
(- x quadratic) 3rd power - 3x quadratic (x quartic + 2x-2) (three quarters a sixth power X second power + six fifths a third power X fourth power -0.9ax third power) / three fifths ax ²
1、
Original formula = - x ^ 6-3x ^ 6-6X ³+ 6x ²
=-4x^6-6x ³+ 6x ²
2、
Original formula = (3 / 4) a ^ 6x ²/ (3/5)ax ²+ (6/5)a ³ x^4/(3/5)ax ²- 0.9ax ³/ (3/5)ax ²
=(4/5)a^5+2a ² x ²- (3/2)x
Given the sum of the 5th power of equation (3x + 1) = the 5th power of ax plus the 4th power of BX plus the 3rd power of Cx plus the quadratic power of DX plus ex plus F, find the algebraic formula - A + B-C + D-E + F
(3x + 1)^5 = ax^5 + bx^4 + cx ³ + dx ² + ex + f
Substitute x = - 1 into the above formula to obtain:
(-3 + 1)^5 = -a + b - c + d - e + f
-32 = -a + b - c + d - e + f
-a + b - c + d - e + f = -32
RELATED INFORMATIONS
- 1. If (3x + 1) 5 = ax5 + bx4 + cx3 + DX2 + ex + F, the value of A-B + C-D + E-F is __
- 2. 6X5 power - 15x quartic power + 3x3 power - 3x square + X + 1 divided by 3x square, the remainder formula is x + 1 to find the quotient
- 3. Given that f (x) is an even function, G (x) is an odd function, and f (x) + G (x) = x quartic + 3x-2, find f (x) and G (x)
- 4. F (x) is a function with t as the period. Is the definite integral of F (x) from 0 to a equal to the definite integral of F (x) from t to a + T? Why
- 5. Let the function f (x) be a function with t as the period, prove that f (AX + b) (A and B are positive numbers) is also a periodic function, and find its period
- 6. Let the function f (x) be continuous on the interval [a, b], differentiable in (a, b), and ∫ (a, b) f (x) DX = f (b) (B-A). It is proved that there is at least Let the function f (x) be continuous on the interval [a, b], differentiable in (a, b), and ∫ (a, b) f (x) DX = f (b) (B-A). It is proved that there is at least one point in (a, b) ζ, Make f '（ ζ)= 0 Reference. It seems that the teacher said to use the integral mean value theorem first and then Rolle's theorem.
- 7. Let a > 0, the x power of F (x) = E / A + the x power of a / E be an odd function. 1. Find a, 2. Prove that it is an increasing function on [0. Positive no group]
- 8. Let the function f (x) = 2 to the power of X / A + A / 2 to the power of X be an even function to find the value of A
- 9. It is known that f (x) = the x power of 10 plus the x power of 10 / 10 minus the negative x power of 10, Find its value range
- 10. Given the power of X + 3x + 5 = 7, then the power of X + 3x = (), 3 (power of X + 3x) - 2 = ()
- 11. The function f (x) = the x power of 2 plus the zero of 3x, find its interval,
- 12. What is the minimum positive period of the function y = sin (4th power) x + cos (4th power) x?
- 13. Known function f (x) = 1 2x2-lnx． (1) Find the monotone interval of F (x); (2) If G (x) = - 2 3x3 + X2, it is proved that when x > 1, the image of function f (x) is always above the image of function g (x)
- 14. Let x = 1 and x = 2 be the two extreme points of the function f (x) = alnx + BX ^ 2 + X, if (LNX) '= 1 / x, Judge whether x = 1 and x = 2 are the maximum or minimum of function f (x), and explain the reason
- 15. Given the function f (x) = LNX / x, if a > 0, the function H (x) = XF (x) - x-ax ^ 2 has an extreme value on (0,2), find the value range of real number a
- 16. Arrange 3x to the 3rd power y + xy2nd power - 2y3rd power - 3x2 power according to the descending power of X
- 17. Given that the x power of 10 = 2 and the Y power of 10 = 3, find the value of 3x-2y of 10 The answer is tonight
- 18. What is the slope of the tangent at point (0,2) of the function y = ex plus 1
- 19. Find the variation range of the slope of the tangent of the function y = sin (π / 3-2x)
- 20. The function f (x) = ax-a / X-2 * LNX is known. When a = 1, judge whether the function f (x) has extreme value in its definition domain. If so, find it