Y = the fourth power of cosx - the fourth power of 2sinxcosx SiNx, find the minimum positive period of Y When x belongs to [0, Pie / 2], find the maximum and minimum value of Y

Y = the fourth power of cosx - the fourth power of 2sinxcosx SiNx, find the minimum positive period of Y When x belongs to [0, Pie / 2], find the maximum and minimum value of Y

Y = quartic of cosx - quartic of 2sinxcosx SiNx → y = quartic of cosx - quartic of 2sinxcosx SiNx - 2sinxcosx → y = (quadratic of cosx + quadratic of SiNx) (quadratic of cosx - quadratic of SiNx) - 2sinxcosx → y = 1 * (quadratic of cosx - quadratic of SiNx) - 2sinxcosx → y

Find the period of the fourth power of the culvert number y = cosx - the fourth power of SiNx

Y = the fourth power of cosx - the fourth power of SiNx
=(cos^x+sin^x)(cos^x-sin^x)
=(cos^x-sin^x)
=cos2x
Period π

Is the derivative of (1-sinx) equal to cosx or - cosx?

(1－sinx)'
=1'－(sinx)'
=0－cosx
=－cosx

Y is the derivative of 1 plus SiNx divided by 1 plus cosx Please don't answer indiscriminately

y=u/v
y'=(u'v-v'u/v^2
y=(1+sinx)/(1+cosx)
y'=(cosx(1+cosx)+sinx(1+sinx))/(1+cosx)^2=(1+cosx+sinx)/(1+cosx)^2

How to find the derivative of COS (1 + x)?

[cos(1+x)]=-sin(1+x)*(1+x)'=-sin(1+x)

Derivative of 1-cos (x ^ 2)

f=1-cos(x^2)
df=sin(x^2)*2*x*dx
That is, the derivative of 1-cos (x ^ 2) is 2 * x * sin (x ^ 2)