If the equations of X and y, x = 3-2t, Y-5 = 3T, then use the algebraic formula containing x to express y, which is correct

t=(3-x)/2
Substitute Y-5 = 3T
Y-5 = 3 / 2 (3-x)
I.e. y = 19 / 2-3 / 2x

Find the first derivative dy / DX and the second derivative of the function y = y (x) determined by x = t + T ^ 2, y = T-T ^ 3

y/x=(t-t^3)/(t+t^2)=1-t
Then t = 1-y / X
Bring in x = t + T ^ 2 to get:
x=1-y/x +1+y^2/x^2-2y/x
That is, x ^ 3 = x ^ 2-xy + x ^ 2 + y ^ 2-2xy
And then it will?

It is known that x = 2T + 3, y = 3t-1 ⑴ use the algebraic formula containing x to represent y ⑵ use the algebraic formula containing y to represent X

(1) x = 2T + 3, then t = (x-3) / 2 is substituted into y = 3t-1 to get y = 3 (x-3) / 2-1, so y = 3x / 2-11 / 2
(2) y = 3t-1, then t = (y + 1) / 3 is substituted into x = 2T + 3 to get x = 2 (y + 1) / 3 + 3, so x = 2Y / 3 + 11 / 3

Given the equations 4x + 3Y = 3T + 2x-y = 1-2T, please use the algebraic formula containing x to express y

Multiply the formula on the left by 2 and the formula on the right by 3
Last y = (5-14x) / 3

Known: x = (1-T) / (1 + T), y = (3-2t) / (2-3T), please use the algebraic formula of X to express y

x=(1-t)/(1+t)
1-t=x(1+t);
t=(1-x)/(x+1);
Substitute t into the Y algebra,
After simplification, y = (5x + 1) / (5x-1) is obtained

If x = (1-T) / (1 + T) y = (2-3T) / (3-2t), use the algebraic formula of X to express y

x+xt=1-t
t=(1-x)/x+1)
3y-2yt=2-3t
t=(3y-2)/(2y-3)
(3y-2)/(2y-3)=(1-x)/(x+1)
3xy+3y-2x-2=2y-3-2xy+3x
5xy+y=5x-1
y=(5x-1)/(5x+1)

If the equations of X and y, x = 3-2t, Y-5 = 3T, then use the algebraic formula containing x to express y, which is correct