Let z = f (XZ, Z / y) determine the function of Z as X, y to find DZ

Let z = f (XZ, Z / y) determine the function of Z as X, y to find DZ

F record the partial derivative of the first variable as F1 and the partial derivative of the second variable as F2,
DZ = F1 * D (XZ) + F2 * D (Z / y)... [Note: if it is completely written, it is F1 (XZ, Z / y), and so is F2]
=f1*(xdz+zdx)+f2*(dz/y-zdy/y^2),
(1-xf1-f2/y)dz=zf1dx-(zf2/y^2)dy,
dz=[zf1dx-(zf2/y^2)dy]/(1-xf1-f2/y).

F (x, y, z) = x ^ 3Y ^ 2Z ^ 2, where Z is the implicit function determined by equation x ^ 3 + y ^ 3 + Z ^ 3-3xyz = 0. Try to find FX (- 1,0,1)

First, let (x, y, z) = x ^ 3 + y ^ 3 + Z ^ 3-3xyz
gx=3x^2-3yz gz=3z^2-3xy
zx=-(gx/gz)=-(3x^2-3yz)/(3z^2-3xy)=-(x^2-yz)/(z^2-xy)
Let's take the derivative of F (x, y, z) (in this case, y can be regarded as a constant and Z as a function of x)
fx=3x^2z^2+x^3*2z*zx
=3x^2z^2-x^3*2z(x^2-yz)/(z^2-xy)
Substitute (- 1,0,1)
FX = 3 * 1 * 2 * 1 - (- 1) * 2 * 1 / 1 = 8

If you want to ask high numbers, Given f (x, y, z) = 0; how to find the second derivative of Z to x? I know the first order is δ z/ δ x=-(Fx/Fz); How to use FX and FZ and FXX, fzz, fzx, FXZ to express the second partial derivative of Z to x? I don't understand how to calculate the partial derivative of this type of composite function. Please help me. Thank you now

δ ( δ z/ δ x)/ δ x==-([Fxx*Fz-Fzx*Fx]/(Fz)^2)
Others are similar

High number implicit function Y ^ y = X. determine that y is a function of X and find dy Is y to the power of Y·

Take logarithm on both sides:
So ylny = LNX
Take the derivative of X on both sides. Note that y is a function of X. taking the derivative of Y is essentially a derivative of a composite function
Then (ylny) '= (LNX)'
Y'lny + y × 1/y × y'=1/x
So (LNY + 1) × y'=1/x
So y '= 1 / [x (LNY + 1)]

Find the volume bottom radius of the cylinder is 3 and the height is 5

Hope naked oats,
three point one four × three × three × 5=141.3

Given that the radius of the bottom surface of the cylinder is 3cm, the relationship between the volume y (cubic centimeter) and the height x (centimeter) of the cylinder is

Cylinder volume = bottom area × high
Bottom area = 3 ² π=9π
y=9π/X