What does the architectural drawing symbol DK mean? The position of dk1512 on the plan door is shown on the drawing Another door is not DK * * but mk1927. What do they mean?

What does the architectural drawing symbol DK mean? The position of dk1512 on the plan door is shown on the drawing Another door is not DK * * but mk1927. What do they mean?

Dk1512 indicates that the width of the opening is 1500 mm and the height is 1200 mm
Mk1927 means the width of the door is 1900 mm and the height is 2700 mm

The cutting position of the building section shall be indicated in the ground floor plan,

According to the unified standard for architectural drawing of buildings, the cutting symbol of the sectional drawing of buildings (structures) should be noted on the plan of ± 0.000 elevation or the first floor plan

What are the main contents of the dimensioning of the plan in the building drawing

The outer dimension is marked in the horizontal direction and vertical direction respectively. The outermost dimension marks the total length and total width of the house in the horizontal direction, which is called the total size; the middle dimension indicates the opening and depth of the house, which is called the axis dimension

As shown in the figure, the image of the first order function y = KX + B and the inverse scale function y = M The image of X intersects a (- 3,1) and B (2, n). The straight line AB intersects X axis and Y axis at D and C (1) The analytic expressions of the inverse proportional function and the first order function are obtained; (2) Seek ad CD value

(1) Substitute x = - 3, y = 1 into y = M
x. Conclusion: M = - 3
The analytic formula of inverse proportional function is y = − 3
x.
Replace x = 2, y = n with y = - 3
X is n = - 3
2.
Y = 3, x = 3
2 into y = KX + B respectively
−3k+b=1
2k+b=−3
2 ,
The solution
k=−1
Two
b=−1
2 ,
The analytic formula of the first order function is y = − 1
2x−1
Two
(2) Pass through point a as AE ⊥ X axis at point E
∵ the ordinate of point a is 1,
∴AE=1.
The analytic formula of the first order function is y = − 1
2x−1
2, the coordinates of point C are (0, − 1)
2),
∴OC=1
2.
In RT △ OCD and RT △ ead, ∠ cod = ∠ AED = 90 °, CDO = ∠ ade,
∴Rt△OCD∽Rt△EAD.
∴AD
CD=AE
CO=2.

As shown in the figure, the image of the first order function y = KX + B and the image of the inverse scale function y = m / X intersect at two points a (- 4,2) B (2, n) (1) try to determine the expressions of the inverse proportional function and the first order function (2) find the area of △ AOB

(1) ∵ a (- 4,2) on the image of inverse scale function y = m / X
∴2=m/(-4)
M = - 8
The expression Y-8 is an inverse function
And ∵ B (2, n) is also on the image of the inverse scale function y = - 8 / X
∴2=-8/n
The solution is n = - 4
The coordinates of point B are (2, - 4)
By substituting a (- 4,2) B (2, - 4) into the first order function y = KX + B, we can get the following results
┏2=-4k+b
┗-4=2k+b
The result is that k = - 1
┗ b=-2
The expression of the first order function is: y = - X-2
(2) Let the line AB intersect the Y axis at point C
∵ if x = 0 in y = - X-2, y = - 2,
The coordinates of point C are (0, - 2)
﹤ s △ AOB = s △ AOC + s △ BOC = 1 / 2 × OC × (absolute value of abscissa of a) + 1 / 2 × OC × (absolute value of abscissa of B)
=(1/2)×2×4+(1/2)×2×2
=4+2
=6 (square units)

It is known that the image with inverse scaling function y = K / X intersects with image of degree y = KX + m at a (2,1), B (a, - 4) It is known that the image with the inverse scaling function y = K / X intersects with the image of the first order function y = KX + m at a (2,1), B(a,-4) (1) When x is taken, the value of inverse proportional function is greater than 0? When x is taken, the value of inverse proportional function is greater than that of first order function? Whether the symmetric point P 'where p (- 1,5) intersects the x-axis is on the image of the function y = KX + m?

(1) According to the meaning of the question, a (2,1) is on y = K / x, so there is 1 = K / 2, so k = 2, the inverse proportional function is y = 2 / x, if Y > 0, then 2 / x > 0, the solution x > 0, that is, when x > 0, the value of inverse proportional function is greater than 0;
And B (a, - 4) is on the inverse scale function y = 2 / x, so a = - 1 / 2, k = 2, M = - 3 can be obtained from the image crossing point a (2,1) and B (- 1 / 2, - 4) of the first order function y = KX + M. therefore, the first order function is y = 2x-3. If the value of the inverse proportional function is greater than that of the first order function, only 2 / x > 2x-3 is needed to get 0

As shown in the figure, the image of the first order function y = kx-1 and the image of the inverse scale function y = m / X intersect at two points a and B, where the coordinate of point a is As shown in the figure, the image of the first order function y = kx-1 and the image of the inverse scale function y = m / X intersect at two points a and B, where the coordinates of point a are (2,1)... (1) try to determine the values of K and m; (2) find the coordinates of point B

One
Substituting a coordinate into two function analytic expressions respectively, we get the following results:
1=2k-1
1=m/2
The solution is as follows:
k=1,m=2
Two
The two analytic expressions become
y=x-1
y=2/x
x-1=2/x
x2-x=2
x2-x-2=0
(x+1)(x-2)=0
X = - 1 or x = 2
When x = - 1, y = - 1-1 = - 2
B coordinate is (- 1, - 2)

The first order image of translation function First of all, the value of () remains unchanged, and then the translation of the straight line can be transformed into the translation of () and the translation of () on the straight line can be done; When b > 0, the line y = KX + B can be obtained by translating () unit length of the line y = KX to (); When B < 0, the line y = KX + B can be obtained by translating () unit length of the line y = KX to (); For two lines L1: Y1 = K1X + B1, L2: y2 = k2x + B2 When the line L1 is parallel to L2, K1 () K2, B1 () B2; When the line L1 and L2 intersect at the same point of Y axis, K1 () K2, B1 () B2

First of all, the value of (y) remains unchanged, and then the translation of the line can be transformed into the translation of (x), and then the (distance) on the straight line can be translated; when b > 0, the line y = KX + B can be obtained by translating (b) unit length from the line y = KX to (y); when B < 0, the straight line y = KX + B can be obtained by the straight line y = KX + B

The relationship between the height y (CM) and the time t (H) of a certain kind of candle during the burning process is a linear function. It is known that the original height of the candle is 17 cm, and after 30 minutes of burning, the height is 12 cm (1) Find the function analytic formula of Y with respect to t, and find the value range of independent variable t; (2) The candle was lit at 8:00 p.m., but there was a time when the wind blew out the candle and then lit it again. At 10:00 p.m., the candle was burned out. How many minutes did the candle go out?

(1) Let the analytic formula of the function of Y with respect to t be y = KT + 17, substituting (0.5, 12) to obtain
17+0.5k=12,
K = - 10,
So y = - 10t + 17, and 0 < x < 17 △ [(17-12) ÷ 0.5] = 1.7
(2) From the meaning of the title, 0 = - 10t + 17,
The solution is t = 1.7,
10-8-1.7 = 0.3 hours = 18 minutes
A: the candle went out for 18 minutes

The second grade mathematics first degree function (concept and image) urgent! Explain the reason, can say several questions, 1. If the fruit market stipulates that if the apple is less than 10 kg, including 10 kg, the price is 3 yuan per kg If it is more than 10 kg, then the excess part will be reduced by% 10 per kg. If you buy x (x > 10) kg apple in cash, the payable amount will be y yuan? 2. Given the isosceles right triangle formed by the line y = MX + 5 and the coordinate axis, the expression of this line is?

1. According to the meaning of the question, the following equations are obtained
Y=3X,0≤X≤10;
Y=10×3+3(X-10)(1-10%),X>10.
2. According to the meaning of the title, | x | = | y |, and y = MX + 5, then when x = 0, y = 5, that is, the straight line y = MX + 5 must pass through the (0,5) point
Therefore, there are two straight lines in the first quadrant and the second quadrant respectively. When the straight line is in the first quadrant, the straight line passes through (0,5), (5,0); when the straight line is in the second quadrant, the straight line passes through (0,5), (5,0)
Y = - x + 5 or y = x + 5