Given that the image of the first order function y = KX + m passes through point a (0,1), and K = B of a + C = a + B of C, find the expression of this linear function!

X=0
y=0+m=1
M=1
b+c=ka
a+c=kb
a+b=kc
Add up
2(a+b+c)=k(a+b+c)
So a + B + C = 0 or K = 2
If a + B + C = 0, then a + B = - C, k = (a + b) / C = - 1
So y = 2x + 1 or y = - x + 1

In rectangular coordinate system, the image of the first order function y = KX = + B passes through three points a (2,0), B (0,2), C (m, 3), and finds the expression of this function and the value of M

If a (2,0), B (0,2) are introduced into y = KX = + B, 2K + B = 0,0k + B = 2, k = - 1, B = 2,
The expression of the function is y = - x + 2. By introducing C (m, 3) into the function, we get - M + 2 = 3 and M = - 1

Given that the image of the first order function y = KX + B passes through the point: a (- 2,0), B (m, - 7), C (- 1 / 2, - 3), find the value of M

1. Substituting points a and C into the equation and solving K and B, we can see that the function becomes y = - 2X-4
2. Substituting B into the function, M = 3 / 2

Given the graph of the first order function y = KX + B, through (1,3) and (- 2,0), we find the equation k about X x+k-b The root of X-B = 0

Substituting (1,3) and (- 2,0) into y = KX + B, respectively, results in,
k+b=3
-2k+b=0 ，
The solution
K=1
B=2
So K
x+k-b
X-B = 0 can be reduced to 1
x+1-2
x-2=0，
X = - 4,
Test: when x = - 4, (x + 1) (X-2) = (- 4 + 1) (- 4-2) ≠ 0,
So x = - 4 is the root of the original equation,

The image of the first order function y = KX + B and the image of the inverse scale function y = - 4 / X intersect at two points a (- 1, m) B (n, - 1) (2) Draw the image sketch of the function, and write out the X range that the value of the first function is greater than that of the inverse scale function

(1) ∵ through the point a (- 1, m), B (n, - 1) ᙽ M = - 4 / - 1m = 4N = - 4 / - 1n = 4 ᙽ a (- 1,4), B (4, - 1)

The image of the inverse scale function y = K / X and the first order function y = KX + B intersect at a (1,5) B (n, 1) to find the expression

Substituting a (1,5) into y = K / X
K=5
Substituting B (n, 1) into y = 5 / X
N=5
Function of degree y = KX + B
Replace a (1,5) B (5,1) with
k=-1；b=6
So the inverse scaling function: y = 5 / X
Function of degree y = - x + 6

The image with the inverse scale function y = 12 / X and the image with the first order function y = kx-7 pass through the point P (m, 2) (1) The expression of this linear function (2) If the vertices a and B of the isosceles trapezoid ABCD are on the image of the first order function, and the vertices C and D are on the image of the inverse scale function, the two bottom AD and BC are parallel to the Y axis, and the abscissa of a and B are a and a + 2 respectively, calculate the value of A Just answer the second question. The process The teacher's answer is - 4 or 2 For your reference A = 20 / 3 or 2 / 3 Ad and BC are parallel to the Y axis, so the abscissa of points a and D are the same?

1. Point P is on the inverse proportional function y = 12 / x, so 2 = 12 / m, and M = 6. Point P is on the first order function y = kx-7, so 2 = km-7, k = 9 / 6 = 3 / 2. Therefore, the expression of the first-order function is 7 = 3x / 2-72, ad, BC parallel to the y-axis, so the ordinates of points a and D are the same, and the ordinates of points B and C are the same

Given that the inverse scale function y = K / X and the first order function y = KX + B intersect at the point (- 2,3), the expressions of the inverse scale function and the first order function are obtained respectively Inverse proportional function > first order function, find the value range of X

The inverse proportional function y = - 6 / x, the first order function y = - 6x-9
The value range of X is - 2 〈 x 〈 1 / 2, and X is not equal to 0

The known straight line y = KX + 2 and the inverse proportional function y = m The graph of X intersects two points a and B, and the ordinate of point a is - 1, and the abscissa of point B is 2

Let a (a, - 1), B (2, b), replace these two points into two analytic expressions,
−1＝ m
A
b＝ m
Two
−1＝ak+2
B = 2K + 2
m＝−2
k＝− 3
2 or
m＝6
k＝1
2 ；
The two analytical expressions are y = − 2
x，y=-3
2X + 2 or y = 1
2x+2，y=6
x．

Given the first order function y = x + 2 and the inverse scale function y = K / x, in which the image of the first order function y = x + 2 passes through P (k, 5), try to determine the expression of the inverse scale function

P on y = x + 2
So 5 = K + 2
K=3
P(3,5)
He's also on y = K / X
k=xy=3×5=15
So y = 15 / X

Given that the image of the first order function y = KX + m passes through point a (0,1), and K = B of a + C = a + B of C, find the expression of this linear function!