It is known that the straight line y = KX + B is parallel to y = - 3x + 4, and the intersection point of the line y = 2x + 6 is on the X axis, and the analytic formula of this function is obtained

It is known that the straight line y = KX + B is parallel to y = - 3x + 4, and the intersection point of the line y = 2x + 6 is on the X axis, and the analytic formula of this function is obtained

If the straight line y = KX + B is parallel to y = - 3x + 4, then k = - 3, that is, y = - 3x + B
If y = 0, then x = - 3
X = - 3, y = 0 Generation Y = - 3x + B
0 = 9 + B
b=-9
Therefore, y = - 3x-9

The image of the linear function y = KX + B is parallel to the line y = 1 / 2x-3 and passes through - 1,3

The slopes of parallel lines are equal, so k = 1 / 2
Substituting the point (- 1,3), B = 7 / 2
So y = x / 2 + 7 / 2

Given that the first order function y = KX + B passes through point (1.3) and is parallel to the straight line y = - 2x-6, find the analytic formula of this linear function

∵ the linear function y = KX + B is parallel to the line y = - 2x-6
∴k=-2
The analytic formula of the first order function is y = - 2x + B
Substituting point (1.3) into y = - 2x + B gives B = 5
The analytic formula of the first order function is y = - 2x + 5

Given that the image of the linear function y = KX + B is parallel to the line y-2x and intersects with the point (0, - 3) along the y-axis, the value of K and B is calculated 1. We know that the image of the linear function y = KX + B is parallel to the line y-2x and intersects with the point (0, - 3) of the y-axis, and then find the value of K and B 2. The straight line y = KX + B passes through the point (- 4,9) and intersects the X axis with the point (5,0). Find the value of K and D

1
It is known that the image of the first order function y = KX + B is parallel to y = - 2x
So k = - 2
Because y = KX + B passes through point (0. - 3)
So - 3 = - 2 × 0 + B
So B = - 3
The function is y = - 2x-3
2
Because 9 = - 4K + B, the line goes through (5,0)
So we can set up the equations
9 = - 4K + B and 0 = 5K + B
K = - 1, B = 5

Given the first order function y = KX + B (K ≠ 0) and inverse scale function y = K / 2x, the image intersects at point a (1,1) Forget to hit the bottom, Question: weak point B is a point on the x-axis, passing through △ a0b is a right triangle. Find the coordinates of point B

y=2x-1 y=2/2x
(1,0) and (2,0)
If it is!

The image of the first order function y = 2x + 1 and the image of y = KX + 2 pass through the point (4, a) to find the value of a and K

Substituting point (4, a) into the function of degree y = 2x + 1 gives a = 9
Then we substitute the point (4,9) into y = KX + 2 to get 4K + 2 = 9
k=7/4

It is known that the images of the first order function y = KX + B (k = / 0) and the inverse scale function y = K / 2x intersect at point a (1,2) (1) Find the analytic expression of two functions (2) If point B is a point on the coordinate axis and the triangle AOB is a right triangle, write the coordinates of point B directly

(1) The point a (1,2) is substituted into the inverse proportional function y = K / 2x to obtain k = 4
So the inverse scaling function y = 2 / X
Substituting k = 4; a (1,2) into the first order function y = KX + B (k = / 0)
The solution B = - 2
So the first order function y = 4x-2
(2) B (0,2) or B (1,0)

We know the first order function y = KX + B (K ≠ 0) and the inverse proportional function y = K The image of 2x intersects at point a (1,1) (1) Find two analytic functions; (2) If point B is a point on the x-axis and △ AOB is a right triangle, find the coordinates of point B

(1)  the inverse scale function y = k2x has a (1,1), ᙽ k = 2, ᙽ the inverse scale function is y = 22x = 1X, the first order function y = KX + B = 2x + B, ∵ the first order function y = 2x + B passes through a (1,1), ᙽ 1 = 2 + B, B = - 1,

If the first order function y = KX + B is parallel to y = 2x + 1 and passes through the point (- 3,4), then the expression is as follows:______ .

∵ the linear function y = KX + B is parallel to y = 2x + 1,
ν k = 2, i.e., y = 2x + B,
∵ y = 2x + B passes through the point (- 3,4),
ν 4 = - 6 + B, B = 10,
The first order function is: y = 2x + 10
So the answer is: y = 2x + 10

Known: when the first function y = KX + B, x = 2, y = 1, and the image is parallel to the line y = 2x-1, find its expression

The image is parallel to the line y = 2x-1, so it has: k = 2
When the first order function y = KX + B, x = 2, y = 1, we can get the following results:
1 = 2x2 + B, B = - 3
So we have: y = 2x-3