If the difference between the maximum value and the minimum value of the exponential function y = ax on [- 1, 1] is 1, then the base number a is equal to () A. 1+ Five Two B. −1+ Five Two C. 1± Five Two D. 5±1 Two

When a > 1, the function y = ax is an increasing function in the domain [- 1, 1],  a-a-1 = 1, a = 1+
Five
2，
When 1 > a > 0, the function y = ax is a decreasing function in the domain [- 1, 1], a-1-a = 1, a = − 1+
Five
2，
Therefore, D

If the difference between the maximum value and the minimum value of the exponential function y = ax on [- 1, 1] is 1, then the base number a is equal to () A. 1+ Five Two B. −1+ Five Two C. 1± Five Two D. 5±1 Two

If the difference between the maximum value and the minimum value of the x power of the exponential function y = a on [- 1,1] is 2, then the base number a is equal to? Not quite understand

Because y = a ^ x is a monotonic function ~ so 0

On the range of exponential function and logarithmic function I know how to find the definition field, but how to find the value range has nothing to do with a (y = the x power of a and y = logax)

(1) The definition domain X of the power X of the exponential function y = a belongs to all real numbers, and the range of value is Y > 0. If the value range is required, the function can be substituted according to the corresponding rule on the premise of the definition domain. The value range of the exponential function y has no relationship with a, and a only reflects the monotonicity of the function (a > 1 increasing function; 01 increasing function; 0 0

Image and properties of logarithmic function Concise and clear

In addition to the definition of {x} x, it is necessary to find the properties of {x} x {x} field, and if the definition of {x} is greater than 0, it is necessary to find the properties of {x} field

The image problem of logarithmic function The image of the function y = log (a) x is shifted to the left by one unit and then up by one unit

If the image of the function y = log (a) x is shifted to the left by one unit, y = log (a) (x + 1) is obtained
After one unit up, y = log (a) (x + 1) + 1
The point (2,2) is substituted into the above formula
2=log(a)(2 +1)+1
log(a)3=1
A=3

The problem of logarithmic function image Y = | ln (2-x) | how should this image be drawn? What is the solution to a number minus X image?

First draw the image of Ln (- x), that is, the image of LN x should be symmetrical along the Y axis, and then draw ln (2-x). Different from the principle of left plus right subtraction, to ensure that the logarithm of 2-x > 0, we can know that x < 2 is to shift the image to the right by 2 units, because y = | ln (2-x) &

The image and properties of logarithmic function

Logarithmic function
The general form of logarithmic function is that it is actually the inverse function of exponential function
The figure on the right shows the function graph of different size a
We can see that the graph of logarithmic function is only symmetric graph of graph of exponential function about straight line y = x, because they are inverse functions of each other
(1) The definition domain of logarithmic function is a set of real numbers greater than 0
(2) The range of logarithmic function is the set of all real numbers
(3) The function always passes through (1,0)
(4) When a is greater than 1, it is monotone increasing function and convex; when a is less than 1 and greater than 0, the function is monotone decreasing function and concave
(5) Obviously, the logarithmic function is unbounded

Given that LG2 = a, Lg3 = B, use a, B to denote LG The value of 45 is______ .

Because 45 = 5 × 32,
So LG
45=lg
5×32＝1
2lg10
2+lg3=1
2−a
2+b．
So the answer is: - A
2+b+1
2．

If the difference between the maximum value and the minimum value of the exponential function y = ax on [- 1, 1] is 1, then the base number a is equal to () A. 1+ Five Two B. −1+ Five Two C. 1± Five Two D. 5±1 Two