If the first order function y = KX + B is parallel to y = 2x + 1 and passes through the point (- 3,4), then the expression is? Why is k equal to 2, and why are two parallel K equal to two Why is the value of K equal

If K is equal, we can guarantee parallelism,
The expression is y = 2x + 10

If the first order function y = KX + B is parallel to y = 2x + 1 and passes through the point (- 3,4), then the expression is as follows:______ .

∵ the linear function y = KX + B is parallel to y = 2x + 1,
ν k = 2, i.e., y = 2x + B,
∵ y = 2x + B passes through the point (- 3,4),
ν 4 = - 6 + B, B = 10,
The first order function is: y = 2x + 10
So the answer is: y = 2x + 10

The image of the linear function y = KX + B is parallel to the line y = 3-2x and intersects with the line y = - x + 4 at the same point of the Y axis

If parallel, the x-coefficients are equal
y=-2x+b
y=-x+4
x=0,y=4
Then y = - 2x + B is also over (0,4)
4=0+b
B=4
So it's y = - 2x + 4

If y + X is the intersection point of the two points of the function (a, y + 1) and (b) is the intersection point of the two points, then we can find the intersection point of the two functions

(1) When x = 3, y = 2 × 3-4 = 2 ﹤ a (3,2). From the meaning of the question: B = - 1, substituting a (3,2) into y = kx-1, we get: 3K-1 = 2, k = = 1 ﹤ the analytic formula of the first-order function is y = X-1. (2) when y = 0, 2X-4 = 0, x = 2, B (2,0) X-1 = 0, x = 1, C (1,0) ﹤ BC = 2

The image of the first order function passes through a (2,4), B (0,2) and intersects with X axis at point C (1) The analytic formula of the first order function; (2) The area of △ AOC

(1) Let the analytic formula of the first order function be y = KX + B,
∵ the image passes through two points a (2,4) and B (0,2),
Qi
2k+b＝4
b＝2 ，
The solution
k＝1
b＝2 ，
The analytic formula of the first order function is y = x + 2;
（2）
S△AOC=1
2×OC×AC=1
2×2×4=4，
The area of △ AOC is 4

1. If the image of the first order function y = KX + B (K ≠ 0) passes through points (1, - 1) and is parallel to the straight line 2x + y = 5, then the analytic formula of this function is_______________ Its image passes through_ Quadrant 2. The value of the function < - y = 5 is the analytic range of the function < - x = 5________ 3. In the plane rectangular coordinate system, the straight line y = KX + B (k, B are constants, K ≠ 0, B ＞ 0) can be regarded as the line y = KX moving up B units along the Y axis, then the straight line y = KX is shifted to the right along the X axis by M units (M > 0) 4. If the first order function image passes through the point (1,2), and Y increases with the increase of X, then the analytic formula of this function can be 5. The area bounded by the line y = - 2x + 4 and the two axes is_ 6. In the plane rectangular coordinate system, if the point (x, 4) is on the line segment of the link point (0,8) and (- 4,0), then X= 7. The function y = (M + 6) x + (m-2), when M=_ When m, y is a function of X=______ Y is a positive proportional function of X

Because the function passes through the point (1, - 1), there is K + B = - 1, and because it is parallel to the straight line 2x + y = 5, there is k = - 2
2. Because the first order function is monotone function, there are (1), - 3K + B = - 5, 6K + B = - 2. Or (2) - 3K + B = - 2, 6K + B = - 5. The solution is y = 1 / 3x-4 or y = - 1 / 3x-3
3.y=kx-m
4.y=x+1
Five point four
6.-2
There is something wrong with the problem. Please fix it and I'll solve it

If the image of the first order function y = KX + B is parallel to the straight line y = 2x + 1 and passes through the point P (- 1,2), then the analytic formula of this function is given

K=2
y=2x+b
(- 1,2) into
The analytical formula is obtained
y=2x+4

Given the image crossing point (0,2) of the first order function y = KX + B (K ≠ 0), and the area of the triangle surrounded by two coordinate axes is 2, the analytic formula of this function is obtained

Y = KX + B passing through point (0,2), we can get b = 2
y = kx+2
When y = 0, x = - 2 / K
The area of a triangle enclosed by an axis
S = 1/2 * | -2/k | * 2 = 2
K = ± 1
Therefore, the analytic formula of the first order function is y = x + 2 or y = - x + 2

If the first order function y = KX + B is parallel to the straight line y = - 5x, and the intersection point with the inverse proportional function y = X-2 is (m, 1), then the analytic formula of the first-order function is Because the inverse scaling function y = - 2 / M intersects (m, 1) Therefore - 2 / M = 1 Why is this··· Also, it is the intersection of the inverse scaling function y = - 2 / X at (m, 1)

Because the linear function y = KX + B is parallel to the line y = - 5x,
So there is k = - 5
Therefore, the analytic formula of the original function is as follows:
y=-5x+b
Substituting y = 1 into - 2 of y = x, we get:
x=-2
Therefore, the coordinates of the intersection point are:
（-2.1）
Substituting the above points into the analytic formula of the first order function, we can get the following results:
1=-5*(-2)+b
So B = - 9
Therefore, the analytic formula of the first order function is: y = - 5x-9

If the graph of the first order function y = KX + B is parallel to the straight line y = - 5x, and the intersection point of the image of the inverse scale function y = x molecule 2 is (x, 1), then the analysis of the first order function is given

Because the image of the linear function y = KX + B is parallel to the line y = - 5x, so k = - 5;
Because the intersection point of the image of the first order function y = KX + B and the image of the inverse scale function y = x molecule 2 is (x, 1), so the intersection point must be on the image of the inverse scale function. Therefore, substituting y = 1 into y = 2 / X, we can get x = - 2, that is, the intersection coordinates are (- 2,1);
By substituting the coordinates of intersection point into the analytic formula y = - 5x + B, B = - 9 is obtained;
So the analytic formula of the first order function is y = - 5x-9

If the first order function y = KX + B is parallel to y = 2x + 1 and passes through the point (- 3,4), then the expression is? Why is k equal to 2, and why are two parallel K equal to two Why is the value of K equal