What is cos ^ 2x sin ^ 2x equal?
cos^2x+sin^2x=1
cos^2x-(1-cos^2x)=2cos^2x-1=cos2x
How can sin (2x + π / 2) be equal to cos (2x) 2X + π / 2 is not in the second quadrant
In this formula, sin (2x + bivariate) = sin2xcos bisection + cos2xsin bisection = cos2x
Why is - π / 4 ≤ 2x - π / 4 ≤ 3 π / 4 equal to - radical 2 / 2 ≤ sin (2x - π / 4) ≤ 1
When - π / 4 ≤ 2x - π / 4 ≤ 3 π / 4 is not equal to - radical 2 / 2 ≤ sin (2x - π / 4) ≤ 1, but: when - π / 4 ≤ 2x - π / 4 ≤ 3 π / 4, - radical 2 / 2 ≤ sin (2X - π / 4) ≤ 1, let α = 2x - π / 4sin α increase monotonically in the range of α∈ [- π / 4, π / 2], and decrease α = -... In α∈ [π / 2,3 π / 4]
Is sin ^ 2x + cos ^ 2x + 1 equal to?
Two
If cos (x + 30 °) + SiN x = 4 / 5, cos (2x-60 °) is equal to?
The solution is cosxcos30 ° - sinxsin30 ° + SiNx = 4 / 5
√3/2cosx+1/2sinx=4/5
cos(x-30°)=4/5
cos(x-60°)=cos2(x-30°)=2cos^2(x-60°)-1=2*(4/5)^2=7/25
Let f (COS ^ 2x) = sin ^ 2x, then f '(π / 4) is equal to,
A:
f(cos²x)=sin²x=1-cos²x
So:
f(x)=1-x
The derivative is: F '(x) = - 1
So: F '(π / 4) = - 1
What is sin ^ 2x + cos ^ 2x
sin^2x+cos^2x=1
This is the formula, remember
And sin squared α plus Cos2 α = 1 / 4, Tan α is equal to 0,2
Because 0
Given Sin & = 3 / 5, & belongs to the (0,2) school, find tan2 &, Cos2&
Cos & = 4 / 5
Tan & = 3 / 4
Tan2 - = 24 of 7
Cos2 - = 7 / 25
Sin @ = 3 out of 5 @, belonging to the (0,2 th) school, calculate the values of Tan @ and Cos2 @,
tana=3/4
cos2a=1-2sina^2=7/25