Reduction function f (x) = cos2x / sin (45 '- x)

Reduction function f (x) = cos2x / sin (45 '- x)

f(x)=cos2x/sin(45°-x)
= (cos^2x-sin^2x)/(sin45°cosx-cos45°sinx)
= (cosx+sinx)(cosx-sinx) / [√2/2(cosx-sinx)]
= √2(cosx+sinx)
= 2(sinxcos45°+cosxsin45°)
= 2sin(x+45°)

It is urgent to simplify logic function with formula method, Simplify logic function with formula method, l = AD + a'd + AB + a'c + BD + ab'ef + b'ef, please help,

L=AD+A'D+AB+A'C+BD+AB'EF+B'EF
L=D+AB+A'C+BD+AB'EF+B'EF
L=D+AB+A'C+AB'EF+B'EF
L=D+AB+A'C+B'EF

Logic function, reduced to the simplest and or expression 1. A (a'c + BD) + B (c + de) + BC 'the answer is B' means not

Aa'c + abd + BC + BDE + BC '
Where aa'c = 0 (complementary law)
BC + BC '= B (associative law, complementary law)
So the formula is simplified to B + abd + BDE = B (1 + AD + de) = B
So the final answer is a (a'c + BD) + B (c + de) + BC '= B

The function y = | X-2 | - | x + 2 |, X is any real number. Simplify the expression of function y

There are two points on the number axis: x = 2 and x = - 2
Between districts
1.x

If the line x = π / 6 is a symmetric axis of the image of the function y = asinx + bcosx, what is the inclination angle of the line ax + by + C = 0

Suppose that tant = B / A, 1 / cost = √ (a ^ 2 + B ^ 2) / A
y=asinx+bcosx
=a(sinx+tantcosx)
=√(a^2+b^2)sin(x+t),x=π/6
x+t=π/2
t=π/3,arctana/b=π/6
The inclination angle of AX + by + C = 0
π-arctan(a/b)=5π/6

Let a symmetric axis equation of the image of the function F X = asinx bcosx be x = π / 4, then the inclination angle of the line ax + by + C = 0 is

From the problem design, for any x ∈ R, there is always f [(π / 2) - x] = f (x). That is, asin [(π / 2) - x] - bcos [(π / 2) - x] = asinx bcosx. = = > acosx bsinx = asinx bcosx. = = > (a + b) (SiNx cosx) = 0. = = > A + B = 0. = = > A = - B. the slope of the line ax + by + C = 0 K = - A / b = 1

If the symmetric axis of the image of the function f (x) = asinx bcosx is a straight line x = π / 4, then a + B = O. the judgment is correct and needs to be analyzed

∵ the function f (x) = asinx bcosx image is x = π / 4
∴f(0)= f(π/2)
asin0-bcos0=asin (π/2)-bcos(π/2)
∴-b=a
/ / A + B = O is correct

If the line x = Pai / 6 is an axis of symmetry of the image of the function y = asinx + bcosx, then the tilt angle of the line ax + by + C = 0 is?

First of all, by using the formula of one of two, then y = √ a ^ 2 + B ^ 2 sin (x + ψ) Tan ψ = B / A, and ψ and coordinates (a, b) are in the same quadrant
Since the symmetry axis is told to be x = π / 6, the maximum or minimum value of Y is taken when x = π / 6
Let π / 6 + ψ = π / 2, then ψ = π / 3, Tan ψ = √ 3 A / b = √ 3 / 3; when x = π / 6 is the minimum value, Tan ψ = √ 3; then the slope of the straight line is - √ 3 / 3, and the inclination angle of the line is 150 °

Let f (x) = asinx bcosx image be x = π 4, then the inclination angle of the line ax by + C = 0 is () A. π Four B. 3π Four C. π Three D. 2π Three

When x is the axis of symmetry, the value of function is maximum or minimum
That is, a − B
2=
a2+b2,
The solution is: a + B = 0
Slope k = a
b=−1,
Ψ the inclination angle of the line ax by + C = 0 is α = 3 π
4.
Therefore, B

If a symmetric axis equation of the function y = asinx-bcosx is x = π / 4, then the inclination angle of the line ax by + C = 0 is? It is analyzed in reference books The analysis of the reference book is: y = √ (a 2 + B 2) * sin (x - α), where Tan α = B / A, then x - α = k π + π / 2 (k belongs to Z). Why X - α = k π + π / 2 is not clear

Consider x-a as a whole, let C = x-a, then y = *The axis of symmetry of sinc, y is C = k paipai / 2. It's troublesome to type on your mobile phone. If you can't find the symbols, you can understand them