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Find the function y = 4cos (x / 3), 0
y=4cos（x/3）
X = 3 arccos (Y / 4)
The inverse function is: y = 3arccos (x / 4)
The definition domain of inverse function is the value range of the original function,
Zero
Find y = 3 ^ x (0
The definition domain of inverse function is the original function range
Zero
If there is an inverse function in F (x), f (x) = x + 1 / X; (0,1]
F '(x) = 1-1 / x? When 0
Please help to find the inverse function of y = 4cosx / 3, 0 ∠ x ∠π and its definition domain. Thank you!
Definition of inverse function (4, 3, s)
The inverse function of y = 2 ^ x is y = log2 X. isn't the definition domain and the range different
The range of y = 2 ^ x is the domain of its inverse function y = log2 X
The definition domain of y = 2 ^ x is the range of its inverse function y = log2 X
Find the inverse function of the function y = log2 (2x + 3) (x is greater than minus three thirds) and the definition and range of the inverse function
y=2^(x-1)-3/2
Definition domain: R
> - 2
If the domain of the inverse function of the function y = log2 x + 2 is (3, + ∞), then the domain of the function is
Is the 2 of 2x in y = log2x + 2 the bottom of log? If so, the answer is as follows:
If the definition domain of the inverse function of the function is (3, + ∞), then the value range of the function is (3, + ∞)
Then log2x > 1, since the logarithm of log base 2 is an increasing function, x > 2 is obtained
So the definition domain is (2, + ∞)
It is known that the inverse function of y = (1-2 ^ x) / (1 + 2 ^ x) is y ^ (- 1) = log2 (1-x) / (1 + x). Its definition domain does not need to calculate the value range of the original function Only if the log true number is greater than 0, the result is - 1
The value range of "y = log2 (1-x) / (1 + x) should not be
Is the definition domain of inverse function based on the range of the original function or according to the good inverse function? Sometimes, after finding the expression of the inverse function, I don't know what to do with the definition field. Should we directly use the value range of the original function or determine according to the good expression? For example, the root sign is greater than or equal to 0
The definition domain of inverse function is based on the value range of the original function, which must be correct
The definition domain of inverse function is the range of original function, so is the range of inverse function the domain of original function
yes.
RELATED INFORMATIONS
- 1. Why is the definition domain of inverse function the range of original function?
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