It is known that the function y = f (x) is an odd function. When x is greater than or equal to 0, f (x) = 3x + 1. If the inverse function of F (x) is y = g (x), then G (negative 8) =? Urgent

Because the inverse function of F (x) is y = g (x),
So g (- 8) = - G (8)
That is, f (x) = 3x + 1 = 8
X = 7 / 3
So g (8) = 7 / 3
So g (- 8) = - 7 / 3

It is known that the inverse function of the function f (x) = 2 ^ X-1 is f ^ - 1 (x), G (x) = log4 (3x + 1) (1) If f ^ - 1 (x) < = g (x), find the value range D of X (2) Let the function H (x) = g (x) - 1 / 2 times f ^ - 1 (x), when the value range of function H (x) Mainly want to know how to find f ^ - 1 (x)

1) Let y = 2 ^ X-1 > 0-1 = - 1
X = log2 (y + 1) is obtained
Inverse function f ^ - 1 (x) = log2 (x + 1), x > - 1
Let H (x) = f ^ - 1 (x) - G (x) = log2 (x + 1) - log4 (3x + 1) = log4 [(x + 1) ^ 2 / (3x + 1)]

Y = x ^ 3-3x ^ 2 + 3x + 1 inverse function Help to calculate the inverse function of y = x ^ 3-3x ^ 2 + 3x + 1

y-2=x³-3x²+3x-1=(x-1)³
x-1=(y-2)^(1/3)
So the inverse function y = (X-2) ^ (1 / 3) + 1

Inverse function of y = 3x-1

∵Y=3X-1
∴3X=Y+1
∴X=(Y+1)/3,
When x is exchanged with y, it is the inverse function of y = 3x-1
∴Y=(X+1)/3

Find the inverse function of y = x ^ 3-3x ^ 2-3x + 1

3X^2-6X-3

To find the inverse function of y = 3x + 2, it is better to say how to draw the image

Change x to y,
x=3y+2
y=(x-2)/3
It can be changed into a linear equation y = x / 3-2 / 3, ordinate (0, - 2 / 3), cross (2,0), and then connect two points

Y = 3x + 2 solution x = 3 / Y-2 why x y exchange y = 3 / X-2 is the inverse function of y = 3x + 2

First of all, we should understand the definition of inverse function
Y = 3x + 2, where x is the independent variable and Y is the dependent variable (or can be understood as requiring y)
The inverse function requires x to be represented by an algebraic expression containing y
So we have x = (Y-2) / 3, where y is an independent variable and X is a dependent variable
But as a rule, we use X for the independent variable and y for the dependent variable
So y = (X-2) / 3
First of all, we should understand the definition thoroughly
We look forward to your adoption

The inverse function of F (x) is obtained by giving the logarithm of (x + 2) / (X-2) with a as the base (a is greater than 0 and a is not equal to 1)

(x + 2) / (X-2) times of F (x) = a

If the function y = f (x) is the inverse function of the function y = a ^ x (the x power of a) [a > 0, and a is not equal to], and f (2) = 1, then f (x) =?

y=a^x
Then f (x) = log (a) X
f(2)=log(a)2=1
A=2
f(x)=log(2)x

If f (x) = the image crossing point (2, - 1) of the inverse function of function f (x) = x power of a (a > 0, a is not equal to 1), then a =?

If the inverse function of F (x) = a ^ x is the image crossing point (2, - 1) of F (x) = loga (x), then - 1 = loga (2)
A ^ (- 1) = 2, that is, a = 1 / 2

It is known that the function y = f (x) is an odd function. When x is greater than or equal to 0, f (x) = 3x + 1. If the inverse function of F (x) is y = g (x), then G (negative 8) =? Urgent