Inverse function y = (2x + 2) / (x-1)

Inverse function y = (2x + 2) / (x-1)

y=(x+2)/(x-2)

Given the function y = x ^ 2 + 2x-3, find its inverse function in (- ∞, - 1], and answer the following questions (1) Definition domain of inverse function (2) Monotone interval of inverse function —————— -1] Inverse function in

Because only monotone functions have inverse functions
Y = x ^ 2 + 2x-3 is a parabola with an opening upward. If there is no condition, it is not monotonic in the definition domain (decrease first and then increase)
X-1 is decreasing, so it has to be anti symmetric
The inverse function is as follows:
y=(x+1)^2-4
(x+1)^2=y+4
Because of X

How to find the inverse function of y = (x ^ 1 / 2) / (x-1)?

The inverse function of (x-1) y = √ XXY - √ X-Y = 0 (√ X-Y / 2) 2 = y + Y / / 4 √ X-Y / 2 = √ (y + y 2 / 4) √ x = Y / 2 + √ (y + y 2 / 4) x = Y / / 4 + y + y 2 / 4 + y √ (y + y 2 / 4) is the inverse function of y = x? 2 / 2 + X + X √ (x + X? 2 / 4)

Find the inverse function of y = x ^ 2 + 2x-1. X belongs to [1,2] (can you also tell me how to find the inverse function of a function

y=x^2+2x-1
y=(x+1)^2-2
(x+1)^2=y+2
x+1=√(y+2)
x=√(y+2)-1
The inverse function is y = √ (x + 2) - 1

Inverse function of y = x + 2 / 2x + 1

y=x-2/1-2x

Find the inverse function of y = (1-x) / (1 + x)

y=(1-x)/(1+x)
y(1+x)=1-x
y+xy=1-x
xy+x=1-y
(y+1)x=1-y
x=(1-y)/(y+1)
So the inverse function is y = (1-x) / (x + 1)
If there is anything you don't understand, you can ask,

Inverse function of y = (√ x-1) + 2

y-2=√(x-1)
(y-2)²=x-1
∴x=y²-4y+5
That is, the number of inverse functions is: y = x? - 4x + 5

Find the inverse function of y = 2 ^ (x-1) + 5

y=2^(x-1)+5,y>5
y-5=2^(x-1)
log2(y-5)=x-1
∴x=1+log2(y-5)
x. Y = 1 + log2 (X-5) (x > 5)

What is the inverse function of y = (x-1) ^ 2? Is it divided into two segments? According to the image of the function and its inverse function in the coordinate system, the inverse function of y = (x-1) ^ 2 is symmetric with its own image relative to y = x, then the image of its inverse function has two Y values corresponding to each x value, except x = 0. This does not conform to the definition of function. For each x, there is and only one y value corresponding to it. In addition, what about multi valued function?

You're right. Only a single valued function has an inverse function, so y = (x-1) ^ 2 has no inverse function

If the image of function f (x) passes through the point (0,1), then the image of function f (4-x) passes through the fixed point, and the secondary fixed point is? Yes, this fixed point is But the answer is (1,4), I don't understand

The fixed point should be (4,1), the answer in your book is wrong
x→f(x) x＝0,f(x)＝1.
Change the previous x to 4-x, then: 4-x → f (4-x), 4-x = 0, f (4-x) = 1. That is, when x = 4, f (4-x) = 1, so the fixed point is (4,1)