Given that the root sign x is equal to 1 / 2 of the root y minus the root y, find the square of the fourth power y of the root X of the algebraic formula (1-2y + y ^ 2)

The root x is equal to 1 / 1 of the root y minus the root y, and the square of both sides gives: x = (1 / y + Y - 2)
The square of the fourth power y of radical x (1-2y + y ^ 2)
=x²y²(1-2y+y²)
=（xy）²(1-2y+y²)
=(1-2y+y²)²(1-2y+y²)
=(1-y) ^ 6 or = (XY) ^ 3

If a = 2, then the value of the double radical a - (a-radical a + radical a) is equal to

2 root 2 - (2 + root 2) / (2-root 2) = 2 root 2 - (2 + root 2) ^ 2 / 2
=2 root number 2 - (4 + 4 root number 2 + 2) / 2 = 2 root number 2-3-2 root number 2 = - 3

Given that x = radical 2 + 1, find the value of the square - 2x + the square - X-2 of X

x=√2+1,
x²=3+2√2
﹙x²-x-2﹚／﹙x²-2x+1﹚
=﹙2+√2﹚/2
=1+√2/2

Solution equation: (1) 2x ^ 2-7x-5 = 0 (2) 4x ^ 2 + 9x + 3 = 0 (3) 5x ^ 2-2x-4 = 0 Matching method

In the future, please say in advance
(1)2x^2-7x-5=0
x^2-7x/2=5/2
x^2-7x/2+(7/4)^2=5/2+(7/4)^2
(x-7/2)^2=89/16
x-7/2=±√89/4
x=(7±√89)/4
(2)4x^2+9x+3=0
x^2+9x/4=-3/4
x^2+9x/4+(9/8)^2=-3/4+(9/8)^2
(x+9/8)^2=33/64
x+9/8=±√33/8
x=(-9±√33)/8
(3)5x^2-2x-4=0
x^2-2x/5=4/5
x^2-2x/5+(1/5)^2=4/5+(1/5)^2
(x-1/5)^2=21/25
x-1/5=±√21/5
x=(-1±√21)/5

The solution equation is: (1) - 7x = 2 + 2X-4 (2) 4-2 / 5x = 5 / 2-x (3) 2 / 5x-4 = 6 + 3 / 5x (4) - 2x + 1 = 4x + 4

（1）-7x=2+2x-4
-9x=-2
x=2/9
（2）4-2/5x=5/2-x
3/5x=-3/2
x=-5/2
（3）2/5x-4=6+3/5x
-1/5x=10
x=-50
（4）-2x+1=4x+4
-6x=3
x=-1/2

Correct answer: 20 reward points: 3 / 7X + 1 / 2x = 13 X - 1 / 5x = 8 / 15, 4x + 5x = 18 / 11,

This is the three equation!
3/7X+1/2X=13
6/14X+7/14X=13
13/14X=13
X=14
X -1/5X=8/15
4/5X=8/15
X=2/3
4X+5X=18/11
9X=18/11
X=（18/11）/9
X=2/11
Do not know can also ask me, I wish you in the future study on a higher level!

The solution of the equation is reduced to: (1) x ^ 2-4x + 4 = 0 (2) 5x ^ 2-15x = 0 (3) x ^ 2-5x + 6 = 0 (4) 2x ^ 2-7x + 3 = 0

(1) X ^ 2-4x + 4 = 0 (X-2) ^ 2 = 0 (full square formula), x = 2 (2) 5x ^ 2-15x = 0 5x (x-3) = 0 (extracted common factor) x = 0 or x = 3 (3) x ^ 2-5x + 6 = 0 (X-2) (x-3) = 0 (factorization) x = 2 or x = 3 (4) 2x ^ 2-7x + 3 = 0 (2x-1) (x-3) = 0 (factorization) x = 0.5 or x = 3

5x + 2x = 33.6,7x-4x = 0.75,2x + 7x + 2.1 = 12,56x-32x-119 = 361, and solve the equation

5x+2x=33.6,
7x=33.6;
x=4.8;
7x-4x=0.75,
3x=3/4;
x=1/4;
2x+7x+2.1=12,
9x=8.1;
x=0.9;
56x-32x-119=361
24x=480;
x=20;
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Solve the equation; 5x in 3 + 2x-1 in 6 = 1

(5x+1)/3 - (2x-1)/6=1
2(5x+1)-(2x-1)=6
10x+2-2x+1=6
8x=3
x=-3/8

solve equations （1）2x−1 2−x+2＝5x+2 3−x+3 Six （2）0.4x+0.9 0.5−0.03+0.02x 0.03＝x−5 2．

(1) By removing the denominator, 3 (2x-1) - 6x + 12 = 2 (5x + 2) - (x + 3), and by removing brackets, 6x-3-6x + 12 = 10x + 4-x-3 can be obtained. 6x-6x-10x + x = 4-3 + 3-12 is obtained by removing the denominator, and - 9x = - 8 is obtained by converting the coefficient to 1, x = 89; (2) the original equation can be reduced to 4x + 95-2x + 33 = x − 52, and the denominator is removed

Given that the root sign x is equal to 1 / 2 of the root y minus the root y, find the square of the fourth power y of the root X of the algebraic formula (1-2y + y ^ 2)