Given x? - 3x = 6, find the value of (x + 2) (x + 3) - 2x (x + 1) - 5

Given x? - 3x = 6, find the value of (x + 2) (x + 3) - 2x (x + 1) - 5

(x+2)(x+3)-2x(x+1)-5
=x²+5x+6-2x²-2x-5
=-x²+3x+1
=-(x²-3x)+1
=-6+1
=-5

2x(1/2x²-1）-3x(1/3x²+2/3） [x(x²y²-xy)-y(x²-x³y)]÷3x²y

2x(1/2x²-1）-3x(1/3x²+2/3）
=x³-2x-x³-2x
=-4x;
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
=(x³y²-x²y-x²y+x³y²)÷3x²y
=2xy/3-2/3;
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If (3x) 2 - (2x + 1) (3x-2) = 3 (x + 2) (X-2), then x=

By removing the brackets, we can get: 9x? - 6x? + X + 2 = 3x? - 12
The result is: x = - 14
So the solution of the original equation is x = - 14

2x²+3x-1=0 4/1x²+x-1=0 Solving equations by collocation method

2 (x? 2 + 3 / 2x + 9 / 16) - 9 / 8-1 = 02 (x + 3 / 2) 2 = 17 / 8 (x + 3 / 2)? = 17 / 16x + 3 / 2 = ± Radix 17 / 4x = - 3 / 2 ± Radix 17 / 41 / 4 (x? + 4x + 4) - 1-1 = 01 / 4 (x + 2) mm2 = 2 (x + 2) mm2 = 8x + 2 = ± 2 root 2x = - 2 ± 2 root sign 2

Given a = x ^ - 2x-3, B = 2x ^ - 5, C = 1 / 2x ^ - 7x + 6, find the value of 2A + b-4c

Because a = x? - 2x-3, B = 2x? - 5, C = 1 / 2x? - 7x + 6, 2A + b-4c = 2 (x? - 2x-3) + (2x? - 5) - 4 (1 / 2x? - 7x + 6) = 2x? - 4x-6 + 2x? - 5-2x? + 28x-24 = (2x? + 2x? - 2x) + (- 4x + 28x) + - 6-5-24) = 2

If a = x ^ - 2x-3, B = 2x ^ - 5, C = 1 / 2x ^ - 7x + 6, find the value of a - (b-4c) (^ is the square)

A=x^2-2x-3,B=2x^2-5,C=1/2x^2-7x+6
A-(B-4C)
=A-B+4C
=(x^2-2x-3)-(2x^2-5)+4(1/2x^2-7x+6)
=x^2-2x-3-2x^2+5+2x^2-28x+24
=x^2-30x+26

Solve the equation x? 2 + x-6x + x-12x-5 = x? - 6x + 7x-10

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)
5x/(x-2)(x+3)+(2x-5)/(x+3)(x-4)=(7x-10)/(x-2)(x-4)
5x(x-4)+(2x-5)(x-2)=(7x-10)(x+3)
5x^2-20x+(2x^2-9x+10)=7x^2+11x-30
7x^2-29x+10=7x^2+11x-30
40x=40
X=1
It is proved that x = 1 is the solution of the equation

Factorization of 2x 2 - 7x + 6 = 0

2x²-7x+6=0
（2X-3）（X-2）=0
The results show that X1 = 3 / 2, X2 = 2

Solution 2x? - 7x + 6 < = 0

2x²-7x+6≤0
（2x-3）（x-2）≤0
3/2≤x≤2

Given that x square + X-1 = 0, find the value of the algebraic formula X Cubic power + 2x square + 2009

Because x? 2 + X-1 = 0, so x? 2 = 1-x, the equation is: x? + 2x? + 2009 = x? * x + 2 (1-x) + 2009 = (1-x) * x + 2-2x + 2009 = x-x? + 2-2x + 2009 = x - (1-x) + 2-2x + 2009 = X-1 + X + 2-2x + 2009 = X-1 + X + 2-2x + 2009 = 2010