If the solution sets of inequality (m-1) x > m + 5 and 2x > 8 for X are the same, then the value of M is______ ?

If the solution sets of inequality (m-1) x > m + 5 and 2x > 8 for X are the same, then the value of M is______ ?

2x＞8;
x＞4;
(m-1)x＞m+5;
x＞(m+5)/(m-1);
∴(m+5)/(m-1)=4;
m+5=4m-4;
3m=9;
m=3;
If there is anything you don't understand, you can ask,

Given that the solution set of the inequality 2x-m > - 3 on X is x > - 2, find the value of M

2X > - 3 + m, x > (- 3 + m) / 2, and x > - 2
So (- 3 + m) / 2 = - 2, M = - 1

We know that the inequality system about X is x-m > N, 2x-m

x>n+m=3;
X

It is known that the solution set of x-m ≥ n, 2x-m < 2n + 1 is 3 ≤ x < 5. Find the value of M + n

It is easy to get m = - 3, n = 6, so the result is 45

If the solution set of the inequality x-m > = n, 2x-m < 2N-1 is 3 < = x < = 5, then the value of N / M is It's urgent!

∵x-m>=n
∴x>=m+n
∵2x-m<2n-1
∴x<(m+2n-1)/2
∴m+n=3
(m+2n-1)/2=5
The solution is n = 8, M = - 5
That is, N / M = - 8 / 5

A system of inequalities about X is known x−A≥B If the solution set of 2x − a < 2B + 1 is 3 ≤ x < 5, then B The value of a is______ .

x−A≥B①
2x−A＜2B+1② ，
∵ solve the inequality ①, X ≥ a + B,
By solving the inequality (2), we get: x < 2B + 1 + a
2，
The solution set of inequality system is a + B ≤ x < 2B + 1 + a
2，
∵ inequalities about X
x−A≥B
The solution set of 2x − a < 2B + 1 is 3 ≤ x < 5,
∴A+B=3，2B+1+A
2=5，
The solution is: a = - 3, B = 6,
∴B
A=-2，
So the answer is: - 2

Given the real number x, y, satisfying the requirements of x ^ + y ^ - 2x + 4Y + 5 = 0, try to find the value of X, y, and know the value of X (x + 1) (x + 2) (x + 3) + 1 = 25, and find the value of x 2 + 3x

x^2+y^2-2x+4y+5=0x^2-2x+1+y^2+4y+4=0(x-1)^2+(y+2)^2=0(x-1)^2=0.(y+2)^2=0x=1,y=-2x（x+1）(x+2)(x+3)+1=25x(x+1)(x+2)(x+3)-24=0x(x+3)(x+1)(x+2)-24=0(x^2+3x)(x^2+3x+2)-24=0(x^2+3x)^2+2(x^2+3x)-24=0(x^2+3x...

（3x）²-（2x+1）（3x-2）=3（x+2）（x-2）

（3x）²-（2x+1）（3x-2）=3（x+2）（x-2）
9x²-(6x²-4x+3x-2)=3(x²-4)
9x²-6x²+x+2=3x²-12
x=-2-12
x=-14

To solve the linear equation passing through the intersection of two curves x? + y? + 3x-y = 0 and 3x? + 3Y? + 2x + y = 0 Why? Why? Can you talk about your ideas?

The first formula is three times minus the second formula is the intersection line equation, the answer is: 7x-4y = 0

Find the maximum and minimum values of the quadratic function y = 2x? - 3x + 5 on - 2 ≤ x ≤ 2, and find the corresponding value of X

The symmetry axis of the quadratic function y = 2x ^ 2-3x + 5 is x = 3 / 4;
(the symmetry axis of the quadratic function y = ax ^ 2 + BX + C is x = - B / 2a)
When x = 3 / 4, y = 31 / 8;
∵ 3 / 4 ∈ (2, - 2) and y = 2x ^ 2-3x + 5, the opening is upward,
The minimum value of the function is 31 / 8;
∵|-2-3/4|>|2-3/4|,
When x = - 2, the function gets the maximum value of 19;
A: the maximum and minimum values are 19 and 31 / 8, respectively