Addition and subtraction of fractions (2) 3x / (x-3) 2 - X / 3-x RT

Addition and subtraction of fractions (2) 3x / (x-3) 2 - X / 3-x RT

3x/(x-3)²-x/（3-x）
=（3x+x^2 -3x)/(x-3)^2
=x^2 /(x-3)^2

The addition and subtraction of fraction x 2 + 3x - 4 is 2x - X - 1 is x + 1 + 1

(x + 1) / [(x-1) (x + 4)] (x + 1) / (x-1) + 1 = 2x / [(x-1) (x + 4)] - (x + 1) (x + 4) / [(x-1) (x + 4)] + (x-1) (x + 4)] + (x-1) (x + 4) / [(x-1) (x + 4)] = [2x - (x + 1) (x + 4) + (x-1) (x + 4)] / [(x-1) (x + 4)] = (2x-x-5x-4 + X + 3x-4) / [(x-1) (x + 4 + 4) / [(x-1) (x + 4) (x + 4) (x + 4) (x-1) (x + 4) (x-1) (x + 4) (x-1] = - 8 / [(x-1) (x + 4)

The first 5 / x-3-2x-5 / x ^ 2-3x the second x ^ 2 / x ^ 2-y ^ 2-x / x + y uses the addition and subtraction of fractions

5/(x-3)-(2x-5)/(x^2-3x)=5x/x(x-3)-(2x-5)/x(x-3)=(5x-2x+5)/x(x-3)=(3x+5)/x(x-3) x^2/(x^2-y^2)-x/(x+y )=x²/(x-y)(x+y)-x(x-y)/(x+y)(x-y)=(x²-x²+xy)/(x+y)(x-y)=xy/(x+y)(x-y)

If the value of fraction x-3 / x ^ 2-2x + 1 is a negative number, find the value range of X

The original formula = (x-3) / (x-1) 2
Denominator is not equal to 0
The denominator is a square, greater than or equal to 0
Then the denominator is greater than 0
If the fraction is negative, the molecule is negative
X-3

If the value of fraction | 2x | - 5 / x ^ + 2 is negative, find the value range of X

If the denominator of this fraction is x 2 + 2, which is always greater than 0, then we only need | 2x | - 5 < 0, and the solution is: - 5 / 2
Homework help users November 3, 2017
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If the value of fraction (2x-1) / (3 + x) is negative, find the value range of X

Because (2x-1) / (3 + x)

It is known that the square of fraction 3x is reduced by 2 / 12 and X by 1 / 2, where m is the common factor of the denominator and N is the simplest common denominator of the two fractions If n of M is equal to 8, then x is equal to

It is known that the square of fraction 3x is reduced by 2 / 12 and X by 1 / 2, where m is the common factor of the denominator and N is the simplest common denominator of the two fractions
M=x-2
N=3(x^2-4)
And N of M equals 8,
3(x^2-4)/(x-2)=8
3(x+2)=8
3x+6=8
x=2/3

The simplest common denominator of fraction x ^ 2-x, x ^ 2-3x + 2 and X-2 is________________

x²-x=x(x-1)
x²-3x+2=(x-2)(x-1)
x-2=x-2
The simplest common denominator is x (x-1) (X-2)

Fraction 1 X2 − 3x and 2 The simplest common denominator of x2 − 9 is______ .

∵x2-3x=x（x-3），x2-9=（x+3）（x-3）
The simplest common denominator is x (x + 3) (x-3)

If the square-4 and X-1 / () of the fraction 3x / 4x are of different denominators, the simplest common denominator is the cube-8x of 8x, and the denominator of the second fraction is a monomial

You asked this question very well, but you expressed it badly. Many people would not understand what you wrote
The square-4 and X-1 / () of the fraction 3x / 4x are different denominators, and the simplest common denominator is the cube-8x of 8x
Let's assume that the denominator of the second fraction is the nth degree of ax (monomial), then a must be equal to 8, and X must be three times
So it's an 8 x 3 times