When x = - 2, the fraction is meaningless; when x = 4, the value of fraction is 0, then find the value of a + B

When x = - 2, the fraction is meaningless; when x = 4, the value of fraction is 0, then find the value of a + B

The fraction x + A is divided into x-b. when x = - 2, the fraction is meaningless, that is, the denominator is 0, so - 2 + a = 0, a = 2
When x = 4, the value of the fraction is 0, which means that the molecule is 0, so 4-b = 0, B = 4
So a + B = 2 + 4 = 6

When x = - 4, the fraction X-B of fraction x + B is meaningless. When x = 2, the value of fraction is zero. Find the value of a-b

If there is no meaning, the denominator is 0
Then x + B = - 4 + B = 0
B=4
Equal to zero, the molecule is zero
So x-a = 2-A = 0
A=2
So A-B = - 2

When x is taken, the value of fraction (- x + 3x-2) (x-2x + 3) is 1?

{- x 2 + 3x-2 = 1 and X? - 2x + 3 = 1
The solution is x = 1
{- x 2 + 3x-2 = - 1 and X? - 2x + 3 = - 1
The solution is x = - 3
The value of X is 1 or - 3

It is known that 2x-3 of fraction x + A is meaningful. When x = - 2, it is meaningless. When x = 3, the value is 0. Find the value of a + B

When x = - 2, the meaningless denominator is equal to 0
When x = - 2
x+a=0
-2+a=0
∴a=2
When x = 3, the value is 0 and the molecule is equal to 0
When x = 3
2x-b=0
∴2×3-b=0
∴b=6
∴a+b=2+6=8

When x=______ Fraction 3 X − 1 is meaningless=______ The fraction x2 − 9 The value of X − 3 is 0

When X-1 = 0, that is, x = 1, fraction 3
X − 1 is meaningless;
When
x2−9＝0
When x − 3 ≠ 0, the fraction x2 − 9
When the value of X − 3 is 0, x = - 3 is obtained;
3

When x is taken, the fraction x − 5 (x−2)(x+3)； (1) Meaningless? (2) Meaningful? (3) Is the value zero?

(1) When the denominator (X-2) (x + 3) = 0, that is, x = 2 or x = - 3, the fraction x − 5
(x − 2) (x + 3) is meaningless;
(2) When the denominator (X-2) (x + 3) ≠ 0, that is, X ≠ 2 and X ≠ - 3, the fraction x − 5
(x − 2) (x + 3) is significant;
(3) When the molecule X-5 = 0, that is, x = 5, the value of the fraction is zero

1) When x is taken, the absolute value of fraction X - 3 / x ^ 2-6x + 9 is zero? Meaningless?

(|x|-3)/(x²-6x+9)=(|x|-3)/(x-3)²
①(|x|-3)/(x²-6x+9)=0
Then | x | - 3 = 0, and (x-3) 2 ≠ 0
X = - 3
② (|x|-3) / (x? - 6x + 9) is meaningless
Then (x-3) 2 = 0
X = 3

When x=______ The fraction is 4 − X X − 3 is meaningless=______ The fraction | x | 9 The value of X + 9 equals zero

Fraction 4 − x
If x − 3 is meaningless, then x-3 = 0 and x = 3;
Fraction | x | 9
If the value of X + 9 is equal to zero, then | x | - 9 = 0 and X + 9 ≠ 0, x = 9
So the answer is 3, 9

Where x = 3, find the value of the following fractions

Xsquare + 2x + 1square-x + 1,
=9 + 6 + 1 / 9-3 + 1
=7 out of 16

When_________ The fraction 2x + 3 / 2x-3 is meaningful when_________ The value of the absolute value - 1 of the square of fraction x + 2x + 1 / 1 x is 0

When__ x≠-3/2_______ The fraction 2x + 3 / 2x-3 is meaningful when__ x=0_______ The value of the absolute value - 1 of the square of fraction x + 2x + 1 / 1 x is 0