Please simplify the fraction x? - 2XY + y? 2 / x? - XY △ (XY - 1st power - X - 1st power y), and then evaluate x = 3 - √ 3, y = √ 3

Please simplify the fraction x? - 2XY + y? 2 / x? - XY △ (XY - 1st power - X - 1st power y), and then evaluate x = 3 - √ 3, y = √ 3

X? - 2XY + y? 2 / x? - XY ^ (XY - 1st power - X - 1st power y) = (X-Y) 2 / X (X-Y) / x = (X-Y) / x ^ (X-Y) / xy = (X-Y) / (x + y) (X-Y) / y = Y / (x + y) = √ 3 / (3 - √ 3 + √ 3) = √ 3 / 3

If XY < 0, then √ (x? Y) is reduced to____ .

Because XY < 0, it is a different sign
When x > 0 and Y < 0, there is no solution
When x < 0, Y > 0, the root sign x ^ 2Y = x root y

What is the following fraction x 2 + 2 x 3 = x 2 - 2 x 1

Hello: x 2 + 2 x 3 = x 2 - 2 x 13 (x 2 - 2 x) = x 2 + 2 x 3 x 2 - 6 x = x 2 + 2 x 2 - 8 x = 0 x 2 - 4 x = 0 (x-4) = 0 x 2 = 0 x 2 = 4 because x ≠ 0, x = 4 don't understand, can ask, if help, remember to adopt, thank you

If x = √ 5 + 1 is known, then the value of fraction x? - 2x-9 / x? - 8x-15 is equal to-----

(x/2)^2-(x/2)-1=0
X ^ 2-2x-4 = 0, x = √ 5 + 1 is the root of the equation on the left!
Therefore: (in particular, their method is too troublesome, which is quite easy)
x^2-2x=4
x^2-8=2x-4
The original formula = (4-9) / [x (x ^ 2-8) - 15]
=-5/[x(2x-4)-15]
=-5/(2x^2-4x-15)
=-5/[2(x^2-2x)-15]
=-5/(2*4-15)
=-5/(-7)=5/7

If the value of the fraction X-2 x-6x + 8 equals zero, then the value of X is

(x-4)(x-2)/(x-2)=0
x-4=0
X=4

Requirements: the fractional value is 0 (the numerator is equal to 0)

(x-2)(x+1)=0
Because x is not equal to 2
So x = - 1

If the value of fraction | x | - 2 / x? - X-2 is 0, then x =?

|x|-2/x²-x-2=0
|x|-2/(x-2)(x+1)=0
|x|-2=0
x=±2
When x = 2
The denominator is 0. Meaningless
So x = - 2

The value of fraction X-1 / 2x + 1 is 0, and the value of fraction x + 2 / x 2 + 1 is negative when x()

When x

If the value of fraction (x + 2x of 2) - 1 is positive, negative or 0, find the value range of X!

（x+2x/2）-1
=（x+x）-1
=2x-1
The value is a positive number
2x-1＞0
x＞1/2
The value is negative
2x-1＜0
x＜1/2
The value is zero
2x-1=0
x=1/2

1. If the value of fraction 2x / x + 2-1 is positive, negative or 0, find the range of X 2. Known 1 / X-1 / y = 3. Find the value of 5x + 3xy-5y / x-2xy-y 3. Given that the value of fraction (m-1) (M-3) / m-3m + 2 is zero, find the value of M Only these three. If you don't want to bother to write the process, the teaching method is OK

1. (2x / x + 2) - 1 gives X-2 / x + 2
If the value is a positive number, it is equivalent to (X-2) (x + 2) > 0
If the value is negative, it is equivalent to (X-2) (x + 2) < 0, and the solution is - 2 < x < 2
2、5x+3xy-5y/x-2xy-y =5x+xy-5y/x-y
=It is necessary to (y + 3) / 5x-1?
Using the given relation, we can deform 1 / x = 3 + 1 / y
3. (m-1) (M-3) / m ^ 2-3m + 2 = General partition makes the molecular equation 0
I can't do the second question of gagachu_