It is known that y = x − 1 2 − 3x, when x takes the following values: (1) the value of Y is positive; (2) the value of Y is negative; (3) the value of Y is zero; (4) the fraction is meaningless

It is known that y = x − 1 2 − 3x, when x takes the following values: (1) the value of Y is positive; (2) the value of Y is negative; (3) the value of Y is zero; (4) the fraction is meaningless

When 2
When 3 < x < 1, y is a positive number;
When x > 1 or x < 2
When 3, y is negative;
When x = 1, y is zero;
When x = 2
At 3, the fraction is meaningless

When X-1 of fraction 2-3x is known, what is the value of X? (1) the value of fraction is positive, (2) the value of fraction is negative, (3) the value of fraction is 0

(1) When X-1 / 2-3x > 0 is multiplied by - 1, X-1 / 3x-2 < 0 is equal to (x-1) (3x-2) < 0, i.e. 2 / 3 < x < 1 (2) X-1 / 2-3x < 0 and multiplied by - 1, X-1 / 3x-2 > 0 is equal to (x-1) (3x-2) > 0, that is, x > 1 or x < 2 / 3 (3) X-1 / 2-3x = 0 2-3x ≠ 0 x ≠ 2 / 3x-1 = 0

Given that y = x 2 / 2-3x, what is the value of X when (1) the value of Y is positive? (2) the value of Y is negative? (3) the value of Y is zero? (4) the fraction is meaningless?

(1) Is the value of Y positive?
2-3x>0
X

If y = x ^ 2 / 2-3x, what is the value of X? 1. Y is positive; 2. Y is negative; 3. Y is 0. 4

1.y=x^2/2-3x>0
2.y=x^2/2-3x<0
3..y=x^2/2-3x=0.4
Draw a picture,

It is known that y = x − 1 2 − 3x, when x takes the following values: (1) the value of Y is positive; (2) the value of Y is negative; (3) the value of Y is zero; (4) the fraction is meaningless

When 2
When 3 < x < 1, y is a positive number;
When x > 1 or x < 2
When 3, y is negative;
When x = 1, y is zero;
When x = 2
At 3, the fraction is meaningless

If the values of fractions 5-x and 2-3x are opposite to each other, what is x equal to?

If the values of fractions 5-x and 2-3x are opposite to each other,
Then 1 / (5-x) + 10 / (2-3x) = 0
Multiply both sides of the equation by (5-x) (2-3x) at the same time
2-3x+10(5-x)=0
The solution is x = 4
Test: put x = 4 into the original equation, left = right
So x = 4 is the solution of the original equation

Given that x squared minus 3x is equal to minus 1, find the fraction x plus 1 of X

x²-3x=-1
That is, x 2 + 1 = 3x
x+1/x=3

Solving the fractional equation (5x-4) / (X-2) = (4x + 10) / (3x-6) - 1

(5x-4)/(x-2)=(4x+10)/3(x-2)-1
Multiply both sides by 3 (X-2)
3(5x-4)=4x+10-3(x-2)
15x-12=4x+10-3x+6
15x-12=x+16
14x=28
X=2
After testing, when x = 2, the denominator X-2 = 0, is the root augmentation, and is omitted
So the equation has no solution

Then the square value of + 3x + 4 is the value of the square of the solution!

3x² - 4x + 6 = 9
3x² - 4x = 3
Divide both sides by 3 at the same time
x² - 4x/3 = 1
So x? - 4x / 3 + 6 = 1 + 6 = 7

X squared + 4x + 4 times x square - 4Y square divided by 3x square + 6xy parts x + 2

Divide [(x square + 4x + 4) parts (x square - 4Y Square)] divided by [(3x square + 6xy) fraction (x + 2)] = [(x? - 4Y?) / (x? + 4x + 4)] / [(x + 2) / (3x? + 6xy)] = [(x + 2Y) (x-2y) / {(x + 2) / {(x + 2) / [3x (x + 2Y)]} = 3x (x + 2Y) 2 (x-2y) / (x + 2) 3