If the value of fraction (x + 2x of 2) - 1 is positive, negative or 0, find the value range of X The process should be more specific

If the value of fraction (x + 2x of 2) - 1 is positive, negative or 0, find the value range of X The process should be more specific

2x/(x+2)-1>0
(2x-x-2)/(x+2)>0
(x-2)/(x+2)>0
Division greater than 0
Then both are greater than 0 or both are less than 0
x-2>0,x+2>0
X-2

If the value of fraction (2x 2 + 1) / (x-radical 5) is always a negative number, then the value range of X is

X is less than radical 5

If the value of the Nuo fraction 2x-1 / x + 1 is negative, find the value range of X

(2x-1)/(x+1)

If the value of fraction (2x-1) / (x + 1) is negative, find the value range of X

The original question is equivalent to (2x-1) / (x + 1) 0, x + 1, x > 1 / 2, X X-1, i.e. - 1

Given x + 1 / x = 2, find x? + 2x + 1 / 4x? - 7x + 4

（x²+2x+1）/（4x²-7x+4）
Divide the numerator and denominator by X at the same time
The original formula = (x + 2 + 1 / x) / (4x-7 + 4 / x)
=[(x+1/x)+2]/[4(x+1/x)-7]
=4/(8-7)
=4

Given that x + 1 / x = 2, find the value of (x ^ 2 + 2x + 1) / (4x ^ 2-7x + 4)

According to the condition, we can judge: X ≠ 0,
Therefore, the original formula = (x + 1 / x + 2) / (4x + 4 / X-7) (the numerator and denominator are divided by x ^ 2)
=(x+1/x+2)/[4(x+1/x)-7]
=(2+2)/(8-7)
=4

What is the simplest common denominator of the fraction x 2 - 1 / 4, x 2 - 4x X-2, x 2 + 4x + X-2?

Because 1 of (x 2 - 4) is equal to 1 of [(x + 2) (X-2)],
(X-2) = [x (x-4)] (X-2),
(x 2 + 4x + 4) parts (X-2) = (x + 2) parts (X-2)
Therefore, the simplest common denominator of the above fractions is:
x(x+2)²(x-4)(x-2)

Given x 2 - 4x + 1 = 0, find the fourth power of fraction x + 1 / x 2 Given x 2 - 4x + 1 = 0, find the fourth power of fraction x + 1 / 2, and find the answer and process

The solution of X? 4x + 1 = 0 divided by X is: x + 1 / x-4 = x + 1 / x = 4, the square (x + 1 / x) of both sides = 16, that is, x? + 2 + 1 / x? 2 = 16 ﹣ x? 2 + 1 / x? 2 = 14 ﹣ (x ﹣ 4 + 1) = 1 / (x? 2 + 1 / x?) 1 / (14) = 1 / 14

Reduced fraction x 2 + 3x + 1 / 2 + x 2 + 5x + 1 / 6 + x 2 + 7x + 1 / 12

Hello!
Original formula = 1 / (x + 1) (x + 2) + 1 / (x + 2) (x + 3) + 1 / (x + 3) (x + 4)
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)
=1/(x+1)-1/(x+4)
=3/(x+1)(x+4)
If there is something you don't understand, you can ask it. If you are satisfied, remember to adopt it
If you have any other questions, please accept this question and send it to me for help
Wish you progress!

Given that a (x? 2 + x-C) + B (2x? - X-2) = 7x? 2 + 4x + 3, calculate the value of a? B? C

From a (x? 2 + x-C) + B (2x? 2 - X-2) = 7x? + 4x + 3, we get (a + 2b) x? + (a-b) x - (AC + 2b) = 7x? + 4x + 3,
Therefore, a + 2B = 7, A-B = 4, - (AC + 2b) = 3,
The solution is a = 5, B = 1, C = - 1, therefore, a? B? C = - 25