The absolute fraction of 2x-3x-3x=_____ The fraction is meaningless when X=______ , the fractional value is 0

The absolute fraction of 2x-3x-3x=_____ The fraction is meaningless when X=______ , the fractional value is 0

When x = 3, the fraction is meaningless; when x = 1 / 2, the fraction value is 0

Given the fraction x-3 / x-5x + A, when x = 2, the fraction is meaningless, then a =. When a < 6, how many values of X make the fraction meaningless

When a is equal to 8, the fraction is meaningless
When a is less than 6, the fraction is meaningless only when x is equal to 1. The non integer ones are 1.25, 0.75, 0.5 and 0.25

Given the fraction x-3 / x2 – 5x + A, when x

According to the meaning of the title, when x = 2, the fraction is meaningless,
The denominator = x2-5x + a = 4-5 × 2 + a = a-6 = 0,
∴a=6；
When x2-5x + a = 0, △ = 52-4a = 25-4a,
∵a＜6,
∴△＞0,
The equation x2-5x + a = 0 has two unequal real roots,
The two fractions of X make no sense
Therefore, when a < 6, there are two values of X that make the fraction meaningless
If a < 6, the number of the value of X that makes the fraction meaningless is to judge the case of the root of the quadratic equation with one variable x = 0 when a < 6

Solution of fractional equation: X squared x squared + 2x + 1 + 2x parts x + 1 = 0

(x ^ 2 + 2x + 1 + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 2x + 1 + 2x + 2x + 2x + 1 + 2x + 2x + 2x + 2x + 1 + 2x + 2x + 2x + 2x + 2x + 2x + 1 + 2x + 1 + 2x + 1 + 2x + 1 + 2x + 1 + 2x + 2x + 2x + 1 1

Solving fractional equation: square of X + 8-4x + X + 2x-3 = 2

The deformation is 8-4x of X (x + 3) and 2x-3 = 2 of 3
8-4x + X (2x-3) = 2
X (x + 3) 8 + 2x - 7x = 2
2X + 6x = 8 + 2x-7x
13x=8
x=8/13

The process and test of the fractional equation x-3-x-x-2 = 2x square + 2x / 3,

Remove denominator: 6x-4 (x + 1) = 3 (x-1) de bracket: 6x-4x-4 = 3x-3 move to: 6x-4x-3x = 4-3 merge similar terms: - x = 1 x = - 1 when x = - 1, x? - 1 = 0 2x? + 2x = 0 ﹣ X

To solve the fractional equation, x + 2x of 2 + 1 = 2

Multiply x + 2 on both sides
2x²+1=2x+4
2x²-2x-3=0
x=(1±√7)/2

When x satisfies what condition, the square of fraction x-a / x-2x-3 is equal to 0?

The value of the fraction is equal to 0
Then the numerator is equal to 0 and the denominator is not equal to 0
So x-a = 0
X=a
Denominator = (x-3) (x + 1) ≠ 0
x≠3,x≠-1
therefore
X = A and a ≠ 3 and - 1

When x (x ≠ 0) is ------ what, the square of fraction 2x plus one tenth of X is positive

The value of x ^ 2 in fraction 2x + 1 and the value of numerator x ^ 2 (x ≠ 0) are always greater than 0. To make this a positive fraction, as long as the denominator (2x + 1) > 0, we can solve this inequality, and know that x ＞ - 1 / 2 and X ≠ 0

When x takes what value, the fraction: the square of X + 2x + 1 / X-2 is 0?

Square of X + 2x + 1 / X-2 = 0
(x+1)²=0
x+1=0
x=-1