Known: known: x? + X-1 = 0, what is the value of X? + 2x? + 1999?

Known: known: x? + X-1 = 0, what is the value of X? + 2x? + 1999?

x^3+2x^2+1999=x(x^2+x-1)+(x^2+x-1)+2000=2000

Given the square of x-2x = 1, find the value of (x-1) (2x + 1) - x (x + 1)

(x-1)(2x+1)-x(x+1)
=x²-2x+x-1-x²-x
=x²-2x-1
By introducing x 2 - 2x = 1 into the above formula, the
x²-2x-1
=1-1
=0
That is (x-1) (2x + 1) - x (x + 1) = 0

Known: x = √ 3 + 1, find the value of √ x square / 1 -- 2x + x square

=3

Given that the square of x-2x-1 = 0, then the value of square of X + 1 / 1 of X is

x^2-2x-1=0
x^2-1=2x
x-1/x=2
(x-1 / x) square = 4
Xsquare-2 + (1 / x) square = 4
The square of X + 1 / 2 of x = 6

Given that X-1 of x 2 = 2, the value of X-1 of 2x 2 + 3x 2 of X-1 is______ .

X-1 of x 2 = 2
2x²=x-1
(x-1)/2x²+3x²/(x-1)
=2x²/2x²+3x/2x²
=1+1.5
=2.5

It is known that (3x? - 2x + 1) (x + b) does not contain x? Term. 1. Find the value of B. 2. (3x? - 2x + 1) (x + b) value

(3x? - 2x + 1) (x + b) = 3x? + 3bx? - 2x? - 2bx + X + B; 3b-2 = 0; b = 2 / 3; 2, (3x? - 2x + 1) (x + b) = 3x? - X / 3 + 2 / 3; if you don't understand this question, you can follow it up. If you are satisfied, remember to adopt it. If you have any other questions, please take this question and send it to me for help

If the value of 2x? 3x + 6 is 12, then the value of 3x + 6 of X? 2 is

2x²-3x+6=12
The results are as follows:
When 2x? 3x = 6, there are:
x²-3x/2=3
So we have: x 2 - 2 / 3 x + 6 = 3 + 6 = 9

Given x 2 - 2x = 5, find the value of (x-1) (3x + 1) - (x + 1) 2

∵x²-2x=5
∴（x-1)(3x+1)-(x+1)²
=（3x²-2x-1)-(x²+2x+1)
=2x²-4x-2
=2(x²-2x)-2
=2*5-2
=8

Given x 2 + 2x-5 = 0, find the value of (3x + 7) (x-1) - (X-2) (x + 2)

It is known that x 2 + 2x-5 = 0
Then x 2 + 2x = 5
So,
（3x+7）（x-1）-（x-2）（x+2）
=3x²+4x-7-x²+4
=2x²+4x-3
=2(x²+2x)-3
=2×5-3
=10-3
=7

When x squared + x = 1, calculate the value of 2x (2 - 2x-3 of x) + 4 (x? 2 + 1 x of 12) - 1 / 3 (3x? - 6x-1) emergency

2x(x2-2x-1/3)+4(x2+x/12) - x/3(3x2-6x-1)
=2x3-4x2-2x/3+4x2+x/3-x3+2x2+x/3
=x3+2x2 =x2(x+2)
= (1-x)(x+2) = -(x-1)(x+2)
= -(x2+x-2)
= 1