Given x-5x = 14, find the value of (x-1) (2x-1) - (x + 1) + 1

Given x-5x = 14, find the value of (x-1) (2x-1) - (x + 1) + 1

x-5x=14
-4x=14
x=-7/2
（x-1）（2x-1)-（x+1)+1
=(-7/2-1)×[2×(-7/2)-1]-(-7/2+1)+1
=(-9/2)×(-8)-(-5/2)+1
=79/2

Given x ^ 2 -- 5x = 14, find the value of (x-1) (2x -- 1) - - (X -- 1) ^ 2 + 1 X (x-1) - (x ^ 2-y) = - 3. Find the value of x ^ 2 + y ^ 2-2xy. [2A + b) (2a-b) - (2a-b) ^ 2 + 2B (a-b)] / 4b, where a = 2, B = 1.

X ^ 2-5x-14 = 0 = (X-7) (x + 2) = > x = 7 or - 2
(7-1)(14-1)- (7-1)^2+1=78-36+1=43
(-2-1)(-4-1)-(-2-1)^2+1=7

Given x2-5x = 14, find the value of 2x2-x-2x + 1 - [x2 + 2x + 1] + 1 The detailed solution of the value of x2-5x = 14

X^2-5x=14
->X = - 2 or x = 7
2x^2-x-2x+1-[x^2+2x+1]+1
=x^2-5x+1
=15

Given that x2-5x-14 = 0, find (x-1) × (2x-1) - (x + 1) 2 + 1

Because x? - 5x-14 = 0
So x? - 5x = 14
(x-1)×(2x-1)-(x+1)2+1
=2x²-x-2x+1-(x²+2x+1)+1
=2x²-3x+1-x²-2x-1+1
=x²-5x+1
=14+1=15

Given x * x-5x = 14, find the value of (x-1) (2x-1) - (x + 1) * (x + 1) + 1

(x-1)(2x-1)-(x+1)*(x+1)+1
=(2x²-3x+1)-（x²+2x+1）+1
=2x²-3x+1-x²-2x-1+1
=x²-5x+1
Because x? - 5x = 14
So the original formula = 14 + 1
=15

Given that the square of x minus 5x minus 14 is equal to 0, find the difference of x minus 1 multiplied by 2x minus 1 minus the square of the sum of x plus 1 plus 1

x²-5x-14=0
x²-5x=14
(x-1)(2x-1)-(x+1)²
=2x²-x-2x+1-x²-2x-1
=2x²-3x+1-x²-2x-1
=x²-5x
=14

The square of x-5x = 14, find the square + 1 of (x-1) (2x-1) - (x + 1)

Square + 1 of (x-1) (2x-1) - (x + 1)
=2x^2-3x+1-x^2-1-2x+1
=x^2-5x+2
=14+2=16

Use Qin Jiushao algorithm to find the value of polynomial f (x) = 3x6 + 12x5 + 8x4-3.5x3 + 7.2x2 + 5x-13 at x = 6, and write out the detailed steps

Using Qin Jiushao algorithm f (x) = 3x6 + 12x5 + 8x4-3.5x3 + 7.2x2 + 5x-13
=（（（（（3x+12）x+8）x-3.5）x+7.2）x+5）x-13．
When x = 6, V0 = 3, V1 = 3 × 6 + 12 = 30, V2 = 30 × 6 + 8 = 188, V3 = 188 × 6-3.5 = 1124.5,
v4=1124.5×6+7.2=6747，v5=6747×6+5=40487，v6=40487×6-13=242909．
∴f（6）=242909．

Using Qin Jiushao algorithm to calculate the polynomial f (x) = 3x ^ 4 + 2x ^ 3-5X ^ 2-6x + 4 when x = 0.8, What are the times of multiplication and addition?

To calculate the value of a polynomial of degree n with Qin Jiushao's algorithm requires n times of multiplication and N times of addition, so the value of polynomial f (x) = 3x ^ 4 + 2x ^ 3-5X ^ 2-6x + 4 when x = 0.8 requires 4 times of multiplication and 4 times of addition
X (x (x (x (3x + 2) - 5) - 6) + 4, every calculation is in the form of AX + B
Calculation order:
3x＋2 → 2.6
2.6x－5 → －2.92
－2.92x－6 → －8.336
－8.336x＋4 → －2.6688
The result is -2.6688

Using Qin Jiushao algorithm to find the polynomial f (x) = 7x7 + 6x6 + 5x5 + 4x4 + 3x3 + 2x2 + X, when x = 3, the value of V3 is () A. 27 B. 86 C. 262 D. 789

f（x）=7x7+6x6+5x5+4x4+3x3+2x2+x=（（（（（7x+6）x+5）x+4）x+3）x+2）x+0
So V3 = ((7x + 6) x + 5) x + 4
When x = 3, V3 = ((7 × 3 + 6) × 3 + 5) × 3 + 4 = 262
Therefore, C