Calculation: 2010 power of (- 2) and 2011 power of (- 2)

Calculation: 2010 power of (- 2) and 2011 power of (- 2)

The 2010 power of (- 2) is a positive number, that is, the 2010 power of 2. Put the 2011 power of + (- 2) together (i.e. take the back as a whole) is the 2011 power of - 2, and then put it together. The 2010 power of 2 - the 2011 power of 2 is based on the 2010 power of multiplication allocation rate 2 * (1-2)

Calculation: 2-2 square - 2 cubic - 2 cubic - 2 - 2009 power - 2 - 2010 power + 2 2011 power

2-2²-2³-.-2^2009-2^2010+2^2011
=2-2²(1-2^2009)/(1-2)+2^2011
=2+2²-2^2011+2^2011
=6

How is the negative quadratic of two calculated What about the negative quadratic of 17 of 11

2(-2)=(1\2)*(1\2)
(11\17)(-2)=1\[（11\17)*（11\17)]
The negative nth power of a is equal to the reciprocal of the nth power of A

How to calculate the minus 2 power of 2?

That is to say, the reciprocal of 2 to the second power of 2 is 4, the negative second power of 2 is one fourth of the second power of 2, that is to say, the solution of the negative fifth power of Quarter 2 is the same as that of the reciprocal of the fifth power of 2, and the negative fifth power of 2 is one fifth of the fifth power of 2, that is, the negative 2 power of 1 / 322 = 0.25 2, born is 0 power, and then add 2

How to calculate the minus 2 power of 1 / 2? To process

=1/（1/2）^2=4

It is known that s = 1 + 2 to the negative first power + 2 to the negative 2 power + 2 to the negative 3 power of 2 + +To the minus 1000 power of 2, please calculate the value of S Kneel to ask God to answer! Thank you very much! Please answer in detail~

A:
S = 1 + 2 to the negative first power + 2 to the negative 2 power + 2 to the negative 3 power of 2 + +To the minus 1000 power of 2
2S = 2 + 1 + 2's negative first power + 2's negative 2 power + 2's negative 3 power +... " +The negative 999 power of 2
The minus 1000 power of S = 2-2

Cos squared minus sin (- α) Tan (360 degrees + α)

Cos squared minus sin (- α) Tan (360 degrees + α)
=Tan (α) of COS squared (α) + sin (α)
=Cos squared (α) + cos (α) 1 / 2

Simplification of SIN3 (- α) cos (2 π + α) Tan (- α - π)

sin3(-α)cos(2π+α)tan(-α-π)
=-sin3acosa-tana
=sin3acosatana
=sin3asina

Simplification 1, cos θ * Tan θ 2, (1-sin θ) (1 + sin θ)

cosθ*tanθ =sinθ
（1-sinθ）（1+sinθ）
=1-(sinθ)^2
=(cosθ)^2

Simplify Tan a (COS a-SiN a) + sin a (sin a + Tan a) / 1 + cos a

tan a(cos a-sin a)+sin a(sin a+tan a)/1+cos a=sin a*(cos a-sin a）/cos a +sin a*(sin a+sin a /cos a )/(1+cos a)=sin a-sin a*sin a/cos a +sin a*(sin a/cos a)*(1+cos a )/(1+cos a)=sin a-sin a*sina/cos a...