(- 1001) 7th power × (- 0.125) 6th power × (- 2 / 7) 7th power × (- 4 / 13) 7th power × (- 1 / 11) 7th power (- 3 / 2) 3rd power × (- 3 / 5) 2nd power - 2 and 19 / 5 × 43 / 19 × (- 1 and 1 / 2) 3rd power + (4 / 5) × (- 3 / 2) 3rd power

(- 1001) 7th power × (- 0.125) 6th power × (- 2 / 7) 7th power × (- 4 / 13) 7th power × (- 1 / 11) 7th power (- 3 / 2) 3rd power × (- 3 / 5) 2nd power - 2 and 19 / 5 × 43 / 19 × (- 1 and 1 / 2) 3rd power + (4 / 5) × (- 3 / 2) 3rd power

(1)(-1001)^7×（﹣0.125)^6×（﹣2/7)^7×（﹣4/13)^7×（﹣1/11)^7
=(-7×11×13)^7×（﹣0.125)^6×（﹣2/7)^7×（﹣4/13)^7×（﹣1/11)^7
=(0.125)^6×2^7×4^7
=1/(4×2)^6×2^7×4^7
=2×4
=8
(2) （﹣3/2)^3×（﹣3/5)^2－(43/19)×(19/43)×（﹣3/2)^3+(4/5)×(﹣3/2)^3
=(﹣3/2)^3×[（﹣3/5)^2－(43/19)×(19/43)+4/5]
=(﹣3/2)^3×[（﹣3/5)^2－1+4/5]
=-27/8×[ 9/25-1/5]
=-27/8×4/25
=-27/50

- 1 to the fourth power - 1 of 6 × [2 - (- 3) squared]

- 1 to the fourth power - 1 of 6 × [2 - (- 3) squared]
=-1-1/6×[2-9]
=-1-1/6×（-7）
=-1+7/6
=1/6

Given that x + 1 / x = 3, find the value of (the fourth power of X + the square of X + 1) the square of X

X + 1 / x = 3
ν (the fourth power of X + the square of X + 1) / x
=x²+1+1/x²
=x²+2+1/x²-1
=(x+1/x)²-1
=3²-1
=8
The square of (the fourth power of X + the square of X + 1) the square of x = 1 / 8

Given that x + x 1 = 3, find the value of the square of X + 1 / 2 of X, the fourth power of X + 1 of the fourth power of X

x+1/x=3
Square on both sides
x²+2*x*1/x+1/x²=9
x²+2+1/x²=9
x²+1/x²=7
x²+1/x²=7
square
x^4+2+1/x^4=49
x^4+1/x^4=47

Given the square of 1 + A + a = 0, find the value of 1 + A + A's square + A's 3rd power + A's 4th power + A's 5th power + A's 6th power + A's 7th power + A's 8th power

1+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8
=(1+a+a^2)+(a^3+a^4+a^5)+(a^6+a^7+a^8)
=(1+a+a^2)+a^3(1+a+a^2)+a^6(1+a+a^2)
If 1 + A + A ^ 2 = 0, then the above equation = 0

How to find the 0.7 power of 3

The seventh power of 3 is the arithmetic root of 10

What is the zero power of seven

Any number to the power of 0 is 1!

The limit of (a to the power of x-1) / X when x tends to 0

(a ^ x-1) / X is a 0 / 0 shape
Use the numerator and denominator to get the derivation at the same time
x——>0
（a^x-1）/x=a^xlna=a^0lna=lna

On the limit of X to the power of X The power of LIM x X tends to 0

The power of LIM x
X tends to 0
It belongs to the infinitive of "0 to the power of 0"
First, take the logarithm of X to the power of X, which is xlnx, and then write LNX / (1 / x)
When x tends to 0 (I think x should tend to 0 +), LNX / (1 / x) is an indeterminate form of "infinite ratio infinite". By using the law of lopeda, the derivative of the numerator denominator is calculated respectively, and the limit of xlnx is 0
Note that xlnx is obtained by taking the logarithm of X to the power of X, so the original limit is e ^ 0 = 1

The [1 / x square] power of LIM [x → 0] (SiN x / x), how to find this limit?

This is an infinitive of the ∞ th power of 1
=Lim [x → 0] e * [1 / x square] · ln (SiN x / x)
=E * Lim [x → 0] [1 / x square] · ln (SiN x / x)
=E * Lim [x → 0] [ln (SiN x / x) / x square]
=E * Lim [x → 0] [ln (1 + (SiN x / X - 1)) / xsquare]
=E * Lim [x → 0] [SiN x / X - 1) / x square] [equivalent infinitesimal]
= e*lim[x→0] [ ( sin x - x ) / x³ ]
=E * Lim [x → 0] [cos X - 1) / (3x?) [lobida's Law]
= e*lim[x→0] [ (-1/2x² ) / (3x²) ]
= e*(-1/6)