What is the 99 th power of 9

2.9512665430655275214875348753480226198 × (the 94th power of 10)

What is the 99th power of 2

633825300114114700748351602688

What is the 99 th power of 2 + 98 th power of 2 + 97 th power of 2 + ··· + 2 + 1

Let s = 2 ^ 99 + 2 ^ 98 + 2 ^ 97 +. + 2 + 1
2S=2^100+2^99+2^98+2^97+.+2^2+2
2S-S=2^100-1
S=2^100-1
That is, 2 ^ 99 + 2 ^ 98 + 2 ^ 97 +. + 2 + 1 = 2 ^ 100-1

What is the 99 th power of minus 1 / 2 × 100 th power of negative 2?

The 99th power of - 1 / 2 × the 100th power of - 2
=The 99th power of minus 1 / 2 × the 99th power of minus 2 × 2
=(- 1 × 2) to the 99th power × 2
=The 99th power of (- 1) × 2
=-1×2
=-2

If the ninetieth power of a is greater than the ninetieth power of nine, is a equal to the ninetieth power of nine

a=99⁹/9⁹⁹
=9⁹×11⁹/9⁹⁹
=11⁹/9⁹⁹
b=11⁹/9⁹⁰
So a = B

What's the third power of (a-b) It seems to be the answer to the formula,

(a+b)^3=a^3+3a^2b+3ab^2+b^3
(a-b)^3=a^3-3a^2b+3ab^2-b^3
A ^ 3 is the third power of A

If the a power of 10 is equal to 20, and the B power of 10 is equal to the negative first power of 5, what is the quotient of the value of 9 divided by the 2B power of 3

∵10^a=20,10^b=5^(-1)
∴a=lg20,b=-lg5
∴9^a/3^(2b)
=3^[2(a-b)]
=3^[2(lg20+lg5)]
=3^(2lg100)
=3^(2×2)
=3^4
=81

The a power of 10 is equal to 20, 10 to the B power is equal to one fifth. Find the value of the a power of 3 divided by the B power of 3

Because the a power of 10 is equal to 20, and the B power of 10 is equal to one fifth, so the A-B power of 10 = the (a-b) power of 10 = 20-5 = 100, so A-B = 2, that is, the A-B power of 3 divided by the B power of 3 = 3, the (a-b) power of 3 = the second power of 3 = 9

If the a power of 2 is equal to the power of 5 and the power of B is equal to 10, how much is one part of a plus one part of B?

There are two ways to solve this problem
The first one
2^a=5^b=10
alg2=blg5=1
a=1/lg2
b=1/lg5
1/a+1/b
=lg2+lg5
=lg10
=1
The second type:
The a power of 2 is equal to the B power of 5 = 10
Then 5 ^ (A-1) = 2
2^(b-1)=5
5 ^ (A-1) = 2, both sides take (B-1) power
Then: 5 ^ (A-1) (B-1) = 2 ^ (B-1)
Then: 5 ^ (A-1) (B-1) = 5
So: (A-1) (B-1) = 1
That is: (a + b) / AB = 1
So: 1 / A + 1 / b = 1

The eighth power of the nanometer is 10 microns help..... Bonus points........

5 * 10 to the fourth power micron = 5 * 10 to the fourth power * 10-4cm = 5cm
8 * 10 minus octave meter = 8 * 10 negative octave * 10 ^ 9nm = 80nm

What is the 99 th power of 9