The 2009 power of (- 7) - the 2008 power of - 14 * 7 - the 2007 power of (- 49) * 7
(-7)^2009-14*7^2008-(-49)*7^2007
=-7^2009-2*7^2009+7^2009
=-2*7^2009
If the 2007 power of the reciprocal of the sum of a and B is equal to 1, and the 2009 power of the sum of the opposite number of a and B is equal to 1, then the 2007 power of a + the 2008 power of B is equal to A: B: 2 C: 1 D: 0 which is faster
One
The sum of 2007 to the reciprocal of a and B is equal to
It can be concluded that a + B = 1
The sum of the opposite number of a and B to the power of 2009 is also equal to 1,
It can be concluded that - A + B = 1
a+b=1
-a+b=1
The solution a = 0, B = 1
Then the 2007 power of a + the 2008 power of B is equal to 1
If x is less than 0, how much is the square of x minus the third power of X
X less than 0, x < 0
The square of x minus the third power of x = x - (- x) = 2x
Given that 2x plus 5Y is equal to 4, find the value of the x power of 4 × the Y power of 32
X power of 4 × y power of 32
=2X power of 2 × 5Y power of 2
=The (2x + 5Y) power of 2
=The fourth power of 2
=16
Given that 2x plus 5Y minus 3 equals 0, then what is the power of 4x multiplied by 32y
2x+5y=3 4^x*32^y =2^(2x)*2^(5y) =2^(2x+5y) =2^3 =8
If 2x minus 5Y plus 2 equals 0, find the x power of 4 times (1 / 2 of the Y power of 32)?
2x-5y + 2 = 0 2x-5y = - 2 4 ^ x = 2 ^ (2x) 32 ^ y = (2 ^ 5) ^ y = 2 ^ (5Y), so 4 ^ x * [1 / (32 ^ y)] = 2 ^ (2x-5y) = 2 ^ (- 2) = 1 / 4
If the square of x plus x minus 1 equals 0, find the value of X to the third power plus the square of 2x minus 7 The square of 2x is not enclosed
Because x ^ 2 + X-1 = 0
So x ^ 2 + x = 1
therefore
x^3+2x^2-7=x(x^2+x)+x^2-7=x+x^2-7=1-7=-6
Because the square of x plus x minus 1 equals zero
So the square of x plus x equals 1
Multiply x on both sides
The third power of x plus the square of x equals X
The result is as follows:
The third power of x plus the square of 2x minus 7 equals x plus the square of x minus 7 equals 1 minus 7 equals minus 6
How much is the fourth power of x minus 16? Please give me some detailed process!
x^4-16
=(x^2+4)*(x^2-4)
=(x^2+4)*(x+2)*(x-2)
The square difference formula is used
The third power of x minus 2 times the square of x plus 16 times x minus 32 is the solution of 0
x1=2 x2=4i x3=-4i
The 1 / 3 power of (x + 45) minus the 1 / 3 power of (x-16) is equal to 1 What is the sum of the two roots
(X+45)-(X-16)=[(X+45)^1/3-(x-16)^1/3])[(X+45)^2/3+(X+45)^1/3(x-16)^1/3+(x-16)^2/3]
=[(X+45)^2/3+(X+45)^1/3(x-16)^1/3+(x-16)^2/3]
=[(X+45)^1/3-(x-16)^1/3]^2+3(X+45)^1/3(x-16)^1/3=61
(X+45)^1/3(x-16)^1/3=20
(X+45)(x-16)=8000,X1+ X2=-29