Known equations: the upper 3x - (M-3) y of the | m-2 | - 2 = 1. The lower (M + 1) x = - 2 is a system of bivariate linear equations about X and Y. find the value of M The | m-2 | - 2 power of {3x - (M-3) y ｛（m+1）x=-2

Known equations: the upper 3x - (M-3) y of the | m-2 | - 2 = 1. The lower (M + 1) x = - 2 is a system of bivariate linear equations about X and Y. find the value of M The | m-2 | - 2 power of {3x - (M-3) y ｛（m+1）x=-2

Thank you for your trust in my team. The answers are as follows: because the power (1) (M + 1) x = - 2 (2) of 3x - (M-3) y | m-2 - 2 (1) (M + 1) x = - 2 (2) is a quadratic equation system about X, y, so | m-2 - 2 = 1, and M-3 ≠ 0, M + 1 ≠ 0, M + 1 ≠ 0, from | m-2 - 2 = 1, | m-2 - 2 = 2 = 1: | m-2 124; 3, m-2 = ± 3, M = 5 or M = 5 or M = - 1, and because m is m-2 is M-1, and because m-2 is M-3, m ≠ -

If the M + n power y ^ M-N of - 4x and yn + 1 of 2 / 3x are of the same kind, then the solution of MX + NY = 5 and mx-ny = 1 is?

M + n = 7-m
m-n=n+1
m=3,n=1
3x+2y=5,3x-y=1
x=7/9,y=4/3

Given the equation system: the upper 3x - (M-3) y | m-2 | - 2 = 1. The lower (M + 1) x = 2 is a binary system of linear equations. Find the value of M Let's see the question clearly. The answer on the Internet is 5, but the problem is different. My formula is = 2, they are - 2

The number of Y is one
So | m-2 - 2 = 1
|m-2|=3
m-2=±3
m=-1,m=5
In the second equation, the X coefficient m + 1 ≠ 0
So m = 5

If M-N = 6 and Mn + A2 + 4A + 13 = 0, then (2m + n) a is equal to______ .

From M-N = 6 to M = n + 6, substituting Mn + A2 + 4A + 13 = 0, we get N2 + 6N + 9 + A2 + 4A + 4 = 0
(2) 2 + 2,
The solution is: n = - 3, a = - 2
∴m=3
∴（2m+n）a=（2×3-3）-2=1
9，
So the answer is: 1
9．

If the power of N + m is equal to the power of N + m to the power of 1

From the meaning of the title
M + 2n + 1 of x = the eighth power of X
And ∵ M = 2n + 1
ν m + m of x = the 8th power of X
2m of x = 8th power of X
∴2m=8
M=4
∴4=2n+1
∴n=3／2
mn=4×3／2=6
Hope to adopt with satisfaction, wish study progress

If the square of M + the square of n = 10, Mn = 4, then the cubic power of - M and the cubic power of N-N are equal to

M ^ 2 + n ^ 2 = 10, Mn = 4 then - m ^ 3n-n ^ 3M =?
-m^3n-n^3m
=-mn(m^2+n^2)
=-4*10
=-40

If the M-1 power of the cubic y of 4x is the same as the - n-3 power of the fourth power of - y, then Mn is equal to several

-n-3=3 m-1=4
n=-6 m=5
mn=-6×5=-30

If the m power of X is equal to 3 and the n power of X is equal to 6, then the 3m-2 power of X is equal to

The problem should be x to the power of 3m-2n
The 3m-2 power of x = (the m power of x) is divided by the quadratic power of (x to the nth power)
=The third power of 3 is divided by the second power of 6
=3/4

If the m power of 10 is 2 and the n power of 10 is 3, then the 3M + 2n-2 power of 10 is equal to

10^m=2
10^n=3
10^(3m+2n-2)
=(10^m)³*(10^n)²÷10²
=8*9÷100
=18/25

If the m power of 2 is equal to 3, and the n power of 2 is equal to four, then what is the 3m-2n power of 2? I hope it's colloquial so that I can understand it. I'm not very smart.

2^3m-2n=2^3m/2^2n=2^3*2^M/2^2*2^n=8*3/2*4=3
The 3m-2n of 2 is equal to the 3M power of 2 divided by the 2n power of 2
=The third power of 2 times the m power of 2 divided by the second power of 2 times the n power of 2
=8 times 3 divided by 2 times 4 = 3
The main study is the power of the algorithm