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To the third power of the derivative f (x) = 24x-2x Find the monotone interval of the culvert number
If f (x) = 24x-2x to the third power f '(x) = - 6x ^ 2 + 24, Let f' (x) > 0 - 6x ^ 2 + 24 > 0 6x ^ 2-24
Derivation: y = (X-2) 5th power (2x + 1) 4th power
5(x-2)^4(2x+4)^4+8(2x+1)^3(x-2)^5
X + 1 power of 3 times x + 1 power of 2 = 2x-3 power of 6
3 ^ (x + 1) * 2 ^ (x + 1) = 6 ^ (2x-3)
3 ^ x * 3 * 2 ^ x * 2 = 6 ^ 2x / 6 ^ 3 = both sides divided by 6:
3 ^ x * 2 ^ x = 6 ^ 2x / 36 = simplify the two sides:
6 ^ x = 6 ^ (2x-2)
x=2x-2
X=2
Note: 3 ^ (x + 1) is the (x + 1) power of 3, the same below
/It's a division sign
The nth power of x times 1-x to get the derivative?
Original formula = x ^ N-X ^ (n + 1)
So derivative = NX ^ (n-1) - (n + 1) x ^ n
It is known that the X + 1 power of 3 times the X + 1 power of 2 is equal to the power of 2x-3 of 6, and find the value of X
Looks like we are Baidu space friends, er, help you next
First, the X + 1 power of 3 times the X + 1 power of 2 is equal to the X + 1 power of 6
Thus, we get an equation 6 with the power of X + 1 equal to the power of 2 x-3 of 6
Since all bases are 6, then x + 1 is equal to 2x-3
X = 4
What is the derivative of (x + 1) to the 100th power?
Derivative of (x + 1) to the 100th power = 100 (x + 1) ^ 99
Derivation of 2x to - 2 power
According to the derivative formula y = x ^ n, the derivative is y ′ = NX ^ (n-1), so 2x (- 2) ′ = 2 * (- 2) x ^ (- 3) = - 4x (- 3)
Y = (3x to the third power - 4x) (2x + 1)?
dy/dx=(3x^3-4x)'(2x+1)+(3x^3-4x)(2x+1)'
=(9x^2-4)(2x+1)+(3x^3-4x)(2)
=(18x^3-8x+9x^2-4)+(6X^3-8x)
=24x^3+9x^2-16x-4
Or y = (3x ^ 3-4x) (2x + 1) = 6x ^ 4-8x ^ 2 + 3x ^ 3-4x
dy/dx=24x^3-16x+9x^2-4
Y = 2x to the third power, derivative
y=2x^3
Derivative y '= 2 * 3x ^ 2 = 6x ^ 2
On the derivation of the eighth power of y = (2x + 3), why is 2x + 3 = u equal to dy / Du = (the eighth power of U) '= 8U of the seventh power of 8U
The derivative of u ^ 8 is 8 u ^ 7, and the derivative of u ^ A is a u ^ (A-1)
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