The N + 1 power of 9 minus the 2n power of 3 = 72 to find the value of n

The N + 1 power of 9 minus the 2n power of 3 = 72 to find the value of n

9^(n+1)-3^(2n)=72
9*9^n-9^n=72
8*9^n=72
9^n=9
N=1
above

Given 9N + 1-32n = 72, find the value of n

∵ 9N + 1-32n = 9N + 1-9n = 9N (9-1) = 9N × 8, and 72 = 9 × 8,
When 9N + 1-32n = 72, 9N × 8 = 9 × 8,
∴9n=9，
∴n=1．

-1 / 3 to the power of 2007 times the power of 3 to the power of 2006, and the power of 3 to the power of - 3 to the power of 2006 is equal to

-1 / 3 to the 2007 power and 3 to the 2006 power
(-1/3)^2007*3^2006
=-(1/3^2006*1/3*3^2006)
=-[(1/3*3)^2006*1/3]
=-(1^2006*1/3)
=-1/3
The 2007 power of 3 + the 2006 power of (- 3) is equal to
=3^2007+3^2006
=3^2006*3+3^2006
=3^2006*(3+1)
=3^2006*4

What is the 2008 power of 2 minus the 2006 power of 2?

2 to the 2008 power minus 2 to the 2006 power
=The 2006 power of 2 × (2 ^ - 1)
=3 × 2 to the power of 2006

How to subtract the same base power? For example, what is the 2n power of 2 minus the n power of 2

Extract common factor
The 2n power of 2 minus the n power of 2
=2^n(2^n-1)

If the 2n power of a is equal to 3, find the value of the fourth power of the 3N power of a?

The 2n power of a is equal to 3;
The fourth power of (A's 3N power) = (A's power of n) = (A's 2n power) = (A's 2n power) = (A's 2n power) = (A's 2n power) to the power of 6 = 3? * 3? = 27 * 27 = 729

Let's know that the third power of X is equal to 8, and the 3N power of Y is equal to 27. Find the cubic power of 2m power of x plus the third power of YN defense minus 2m power of X multiplied by n of Y

It is known that x ^ (3m) = 8, y ^ (3n) = 27, x ^ m = 2, y ^ n = 3
Then: [x ^ (2m)] ^ 3 + (y ^ n) ^ 3-x ^ (2m) × (y ^ n)
=4^3+3^3-4×3
=79
The result of the original formula is 79

The 2m power of X is equal to 7. Find the value of the 2n power of 3x minus 13 times the square of X

Is x ^ 2n = 7?
Original formula = 9x ^ 6n-13x ^ 4N
=9(x^2n)³-13(x^2n)²
=9×7³-13×7²
=2450

If the 2N-1 power of 3 + the nth power of 9 = 108, find the value of the nth power of (20-2)

3^(2n-1)+9^n=108
(3^2n)/3+3^2n=108
4(3^2n)/3=108
3^2n=81
3^2n=3^4
2n=4
N=2
that
(20-2)^n
=18^2
=18×18
=324

If the m power of a = 3, and the n power of a = 9, then the (3m-2n) power of a =?

The (3m-2n) power of a
=3M power of a △ 2n power of a
=The third power of (a to the m power) and the second power of (a to the nth power)
=27÷81
=1/3