What is the 2009 power of (√ 3-2) × (√ 3 + 2) to the power of 2010, √18 ÷ √8 × √27/2

What is the 2009 power of (√ 3-2) × (√ 3 + 2) to the power of 2010, √18 ÷ √8 × √27/2

(√ 3-2) to the power of 2009 × (√ 3 + 2) to the power of 2010
=The power of 2009 of (√ 3-2) × (√ 3 + 2) is × (√ 3 + 2)
=The 2009 power of [(√ 3-2) × (√ 3 + 2)] is × (√ 3 + 2)
=(- 1) to the power of 2009 × (√ 3 + 2)
=-(√3+2）

We know that a = 2008, B = 2009, C = 2010. Find the value of a to the 2nd power of a + the 2nd power of B + the 2nd power of C - AB BC AC Please, come on. I'm in a hurry~~~~~~~

a²＋b²＋c²－ab－bc－ca
=(1/2)[(a－b)²＋(b－c)²＋(c－a)²]
=(1/2)[1＋1＋4]
=3

Calculate 2 / 3 to the 2010 power X (1.5) to the 2009 power X (- 1) to the 2008 power = (A.2 / 3 B. - 2 / 3 C.3 / 2 d. - 3 / 2 urgent

2 / 3 to the 2010 power X (1.5) to the 2009 power X (- 1) to the 2008 power
=2 / 3 * 2 / 3's 2009 power * 3 / 2's 2009 power * 1
=The 2009 power of 2 / 3 * (2 / 3 * 3 / 2)
=2 / 3 * 1 to the power of 2009
=2/3*1
=2/3

A simple method is used to calculate the 2008 power of 5 - the 2009 power of 4 times 5 + the 2010 power of 5 Common factor method

5 to the 2008 Power - 4 times 5 to the 2009 power + 5 to the 2010 power
=The 2008 power of 5 - 4 times the 2008 power of 5x5 + the 2008 power of 5? X5
=5 to the 2008 Power (1-20 + 25)
=The 2008 power of 6X5

The second power of 2009 - the second power of 2009 * 2008 the second power of 2010 - the second power of 2008

The second power of 2009 - the second power of 2009 * 2008 the second power of 2010 - the second power of 2008
2010²-2008²
=-----------------------------------
2009²-2009*2008
(2010-2008)(2010+2008)
=-----------------------------------
2009(2009-2008)
2*2009*2
=-----------------------------------
2009*1
=2*2
=4

Given that the m power of 10 is equal to 20 and the nth power of 10 is equal to 0.2, find the value of 2n power of 3 divided by the m power of 9

10^m/10^n=20/0.2=100
10^(m-n)=10^2
m-n=2
To the 2n power of 3 divided by the m power of 9
=9^(n-m)
=9^(-2)=1/81

Given that the m power of 10 = 20 and the nth power of 10 = 1 / 5, then the m power of 9 divided by the 2n power of 3 =?

10^m=20,10^n=1/5
Divide the above two formulas to get
10^m÷10^n=20÷1/5=20×5=100
10^(m-n)=10^2
m-n=2
therefore
9^m÷3^2n
=9^m÷9^n
=9^(m-n)
=9^2
=81

If 10m = 20, 10N = 1 5, find the value of 9m △ 32n

∵10m=20，10n=1
5，
∴10m-n=10m÷10n=100=102，
∴m-n=2，
∴9m÷32n=32m÷32n=32m-2n=32（m-n）=34=81．

It is known that 10m = 0.2, 10N = 4 (1) The value of 2m-n; (2) The value of 9m △ 3N

（1）102m-n(10m)2
10n=0.01，
∵10-2=0.01，
∴2m-n=-2；
（2）9m÷3n=32m-n=3-2=1
9．

The N + 1 power of 9 minus the 2n power of 3 = 72, and find the value of n

9 ^ (n + 1) - 3 ^ (2n) = 3 ^ (2n + 2) - 3 ^ (2n) = [3 ^ (2n)] (3 ^ 2-1) = 8 [3 ^ (2n)] = 72, so 3 ^ (2n) = 9, so 2n = 2, so n = 1