It is known that the m power of 2 = the nth power of 3 and 4 is equal to 11. Find the value of 2 to the 3m-2n power

2^m=3
4^n=2^(2n)=11
2^(3m-2n)
=(2^3m)/2^(2n)
=(2^m)^3/(2^2n)
=27/11

Given a ^ m = 3 and a ^ n = 5, what is the 3m-2n power of a?

Solution: 3m-2n power of a = (3m power of a) / (2n power of a)
If a ^ m = 3, then the 3M power of a = the cubic power of (a ^ m) = the cube of 3 = 27
If a ^ n = 5, then 2n power of a = (a ^ n) square = 5 square = 25
Then the 3m-2n power of a = (3m power of a) / (2n power of a) = 27 / 25

Given that the m power of 10 is equal to 2 and the n power of 10 is equal to 3, what is the 3M + 2n power of 10 equal to?

10^m=2 10^n=3
10^(3m+2n)
=10^3m*10^2n
=(10^m)^3*(10^n)^2
=2^3*3^2
=8*9
=72

Given that the m power of 2 is equal to a and the nth power of 2 is equal to B, the value of (1) 8 to the M + n power and (2) 2 to the M + n power plus 2 to the 3M + 2n power is obtained Hope as soon as possible!

8^(m+n)=(2^3)^(m+n)=2^(3m+3n)=(2^m)^3*(2^n)^3=a^3*b^3
2^(m+n)+2^(3m+2n)=2^m*2^n+2^3m*2^2n=ab+a^3*b^2

Given that the m-th power of 3 is equal to 2, and the n-th power of 9 is equal to 9, find the 3M power-2n power of 3

3 to the power of 3M - 2n
=3M power of 3 / 2n power of 3
=(m power of 3) n power of 3 / 9
=2³/9
=8/9

If we know that the a power of x = 3 and the B power of x = 5, then the 3a-2b power of X is equal to

x^a=3,x^b=5
Then: x ^ (3a-2b) = [x ^ (3a)] / [x ^ (2b)]
=(x^a)³/(x^b)²
=27/25
Wish you happy! Hope to help you, if you do not understand, please ask, I wish you progress_ ∩)O

The second power of a is equal to 2, the third power of B is equal to 3, the fourth power of C is equal to 4, and the fifth power of D is equal to 5

a^2=2
a=√2
a^6=8
b^6=9,
So a

What is the 2010 power of 4 times the 2011 power of 0.25?

(4^2010)*(0.25^2011)
=(4^2010)*(0.25^2010)*0.25
=(4*0.25)^2010*0.25
=(1^2010)*0.25
=0.25

The second power of 2011-2012 * 2010 simple operation

2011^2-2012*2010
=2011^2-(2011+1)(2011-1)
=2011^2-(2011^2-1)
=2011^2-211^2+1
=1

(- 1) + (- 1) to the 2nd power + (- 1) to the 3rd power + +(- 1) to the power of 2011 + (- 1) to the power of 2012 is equal to Can understand the problem to help it

(- 1) + (- 1) to the 2nd power + (- 1) to the 3rd power + +(- 1) to the power of 2011 + (- 1) to the power of 2012
=(-1+1)+(-1+1)+…… +(-1+1)
=0+0+…… +0
=0

It is known that the m power of 2 = the nth power of 3 and 4 is equal to 11. Find the value of 2 to the 3m-2n power