The third power of 2009 + the square of 2009 - the third power of 2009 + 2 * the square of 2009 - 2007

The third power of 2009 + the square of 2009 - the third power of 2009 + 2 * the square of 2009 - 2007

Elder brother, the title is copied wrong
It should be (the third power of 2009 - 2 * 2009? - 2007) / (the third power of 2009 + 2009? 2010)
=[2009²（2009-2）-2007]÷[2009²(2009+1)-2010]
=(2009²×2007-2007）÷（2009²×2010-2010）
=[2007×（2009²-1)]÷[2010×（2009²-1)]
=2007/2010

The 2nd power of 2010 - the 2nd power of 2009 + the 2nd power of 2008 - the 2nd power of 2007 + the 2nd power of 2 - the 2nd power of 1

2010²-2009²+2008²-2007².+2²-1²=(2010²-2009²)+(2008²-2007²)+.+(2²-1²)=(2010+2009)(2010-2009)+(2008+2007)(2008-2007)+… +(2+1)(2-1)=(2010+2009)...

(- 2) 2008 Power * (- 1 / 2) 2008 Power (- 5 / 8) 2009 power * (8 / 5) 2010 power

=2^2008*(1/2）^2008=[2*(2/1)]^2008
=1^2008=1
=-5/8^2009*（8/5）^2010=-5/8^2009*8/5^2009*8/5
=-1*8/5=-8/5

2011 cubic - 2x2011 square - 2009 / 2011 cubic - 2011 SQUARE - 2010

2011 cubic - 2x2011 square - 2009 / 2011 cubic - 2011 SQUARE - 2010
=2011^2*2009-2009/2011^2*2010-2010
=2009(2011^2-1)/2010*(2011^2-1)
=2009/2010

2010 Third Power + 2010 second power - 2011 third power - 2 × 2010 second power - 2008

(2010^3 - 2*2010^2 - 2008)/(2010^3 + 2010^2 - 2011)=(2010^2(2010-2) -2008)/(2010^2(2010 + 1) - 2011)= (2010^2*2008 - 2008)/ (2010^2*2011- 2011)= 2008 *(2010^2- 1)/ ((2010^2- 1)*2011)= 2008/2011

Calculation: 2's 2012 power - 2's 2011 power - 2's 2010 power - 2's 2009 power - 2's 2008 Power -... - 2's - 2's first power

2^2012 - 2^2011 = 2*(2^2011) - 2^2011 = 2^2011.
By analogy, the original formula =... = 2 ^ 2 - 2 = 2

What is the 2009 power of (- 2) minus the 2010 power of (- 2)?

simple form
=(- 2) to the power of 2009 - (- 2) to the power of 2010
=The 2009 power of (- 2) - the 2009 power of (- 2)
=The 2009 power of (- 2) × [1 - (- 2)]
=-The 2009 power of 2 × 3
=-3 × (the 2009 power of 2)

What is the 2010 power of 2 minus the 2009 power of 2

2 to the 2010 power minus 2 to the 2009 power
=2^2010-2^2009
=2*2^2009-2^2009
=(2-1)*2^2009
=2^2009

What is the 2009 power of (- 3) + the 2010 power of (- 3)

2 times 3 to the power of 2009

What is the 2009 power of (- 3) + the 2010 power of (- 3)?

The 2009 power of (- 3) and the 2010 power of (- 3)
=(- 3) to the power of 2009 + (- 3) * - 2 000 times of (- 3)
=(- 2) * - 3)