What is an original function of the third power of the function f (x) = (1 + 2x)? A. The fourth power of 1 / 8 (1 + 2x) B. the square of 3 (1 + 2x) C. The fourth power of 1 / 4 (1 + 2x) d. The third power of 6 (1 + 2x)

What is an original function of the third power of the function f (x) = (1 + 2x)? A. The fourth power of 1 / 8 (1 + 2x) B. the square of 3 (1 + 2x) C. The fourth power of 1 / 4 (1 + 2x) d. The third power of 6 (1 + 2x)

C

The image of the function y = 3 + 2 to the power of X-1 passes through the point A.(2 5) B.(1 3)C.(5 2) D.(3 1)

Replace the abscissa of the four points into the
Only point a
When x = 2, y = 3 + 2 Ψ = 5
The result is equal to the given ordinate
So it goes through point a

What function is e to the power of X

Exponential function the general form of exponential function is y = a ^ x (a > 0 and ≠ 1) (x ∈ R). It is a kind of elementary function. It is defined in the real number field monotone, convex, no upper bound differentiable positive function. A = e exponential function is an important function in mathematics

What is the original function of x times e to the x power

xe^x-e^x

How to find the original function of the (- x) power of E?

The original formula = - x power D (- x) of - ∫ e
=-The (- x) power of E + C

The primitive function of e to the power of X is That is, e has an X on the right and a 2 primitive function on the right of X

The original function is not an elementary function. I don't understand the method,
And sin (x) / x, if you do applications, you can use matlab or maple to calculate,
sym x
int exp(x^2)
Input the above command in MATLAB,
-1/2*i*pi^(1/2)*erf(i*x)

How to get the derivative of x times e to the power of X, what is the process,

Is the derivation of e to the x power or to the x power of E
And the derivative rule of the product is
X times the x power of E = the x power of E + x times the x power of E

How to derive the negative x power of E?

The negative x power of negative e

Derivation of (x * y) power of y = e

Derivation of implicit function in Higher Mathematics:
Let f (x, y) = y-e ^ (x * y) = 0
From the existence theorem of implicit function, dy / DX = - FX / FY is obtained
It means that the derivative of y to X is negative, and the partial derivative of F (x, y) to x divided by the partial derivative of F (x, y) to y
Therefore, the derivative result is: y * e ^ (x * y) / [1-x * e ^ (x * y)]

Y = e to the 1-x power, derivative

(x-1)e^(1-x)