Simplification evaluation: 3x2 + (2x2-3x) - (- 4x + 5x2), where x = 2010

Simplification evaluation: 3x2 + (2x2-3x) - (- 4x + 5x2), where x = 2010

The original formula = 3x2 + 2x2-3x + 4x-5x2 = x,
When x = 2010, the original formula = 2010

Simplification evaluation: 3x? + (2x? - 3x?) - (- 4x + 5x?), where x = 2010

3x²+（2x²-3x²）—（-4x+5x²）
=3x^2+2x^2-3x^2+4x-5x^2
=4x-3x^2
When x = 2010
Original formula = 4 × 2010-3 × (2010) ^ 2
=-12112260

4X? 2x? - (5x? - 3x? + three thirds x-y-1) where x = 3, y = 1, simplify and then evaluate

4X? 2Y? - (5x? - 3Y? + three thirds x-y-1)
=-x²+y²-3/2x+y+1
=-3²+1²-3/2x3+1+1
=-9+1-4.5+2
=-10.5

Simplify and then evaluate: find the value of the polynomial 2x? - 5x + X? + 4x-3x? - 3, where x = 1 / 2

The original formula = (2 + 1-3) x? + (4-5) x-3
=-x-3
=-1/2-3
=-7/2

First, simplify and evaluate: (3x + 20 (3x-2) - 5x (x-1) - (2x-1) 2 Wrong on the top, it's (3x + 2)

solution
(3x+2)(3x-2)-5x(x-1)-(2x-1)²
=(9x²-4)-(5x²-5x)-(4x²-4x+1)
=(9x²-5x²-4x²)+(5x+4x)+(-4-1)
=9x-5

In 2x3-x2-5x + K, if one factor is (X-2), then K value is () A. 2 B. 6 C. -6 D. -2

Let 2x3-x2-5x + k = (X-2) a,
When x = 2, 16-4-10 + k = 0,
K = - 2
Therefore, D

If x-3 is a factor of the polynomial 2x2-5x + m, then M is equal to () A. 6 B. -6 C. 3 D. -3

Substituting x = 3 into the equation 2x2-5x + M = 0, we get 18-15 + M = 0, and the solution is: M = - 3
Therefore, D

After the factorization of the polynomial of 2x ^ 2 + 5x + m, if a factor is (x + 4), then the value of M is

When x = - 4, the value of the original algebraic expression is 0
M = - 12

If X -- 3 is a factor of the polynomial 2x ^ 2-5x + m, then M=

=-3
The reasons are as follows.
The coefficient of the observed quadratic term is two
Therefore, the other factor must be in the form of 2x + C (as for the reason for this, please refer to the content of polynomials in Chapter 1 of higher algebra)
Multiply the comparison coefficient to get the answer

The polynomial a (x 2-2x) 2-2ax (2-x) + A is factorized

a（x2-2x）2-2ax（2-x）+a
=a[（x2-2x）2-2x（2-x）+1]
=a[（x2-2x）2+2（x2-2x）+1]
=a（x2-2x+1）2
=a（x-1）4．