To solve the equation: (1) X-2 / 3 = x-3 / 2 (2) x / 2-5x + 12 / 6 = 1 + 2X-4 / 3 (3) X-2 / 5-x + 3 / 10-2x-5 / 3 + 3 = 0 (4) 5x + 1 / 6 = 9x + 1 / 8-1-x / 3

To solve the equation: (1) X-2 / 3 = x-3 / 2 (2) x / 2-5x + 12 / 6 = 1 + 2X-4 / 3 (3) X-2 / 5-x + 3 / 10-2x-5 / 3 + 3 = 0 (4) 5x + 1 / 6 = 9x + 1 / 8-1-x / 3

There is a problem with the first question
（2）x/2-5x+12/6=1+2x-4/3 (3) x-2/5-x+3/10-2x-5/3+3=0 (4)5x+1/6=9x+1/8-1-x/3
3x-30x+12=6+12x-8 30x- 12-30x+9-60x-50+90=0 -4x+ x/3=1/8-1-1/6
-39x=-14 -60x+37=0 -96x+8x=3-24-4
x=14/39 x=37/60 -88x=-25
x=25/88

Solution equation: 8x-3x = 105 x-0.36x = 16 13.2x + 9x = 33.3x + 1.5x = 17.5x + 1.5x = 17.5x-x = 41.6

8x-3x=105
5x=105
x=21
x-0.36x=16
0.64x=16
x=25
13.2x+9x=33.3
22.2x=33.3
x=1.5
2x+1.5x=17.5
3.5x=17.5
X=5
2x-x=41.6
x=41.6

Solve the equation √ (2x ^ 2-5x + 2) + √ (x ^ 2-7x + 6) = √ (2x ^ 2-3x + 1) + √ (x ^ 2-9x + 7)

√(2x^2-5x+2)+√(x^2-7x+6)=√(2x^2-3x+1)+√(x^2-9x+7),——》√(2x^2-5x+2)-√(2x^2-3x+1)=√(x^2-9x+7)-√(x^2-7x+6),（1）——》[(2x^2-5x+2)-(2x^2-3x+1)]/[√(2x^2-5x+2)+√(2x^2-3x+1)]=[(x^2-9x+7)-(x^2-7x...

Calculation: (5x ^ 2-4x + 1) - (2x ^ 2-5x + 7)

=5x^2-4x+1-2x^2+5x-7
=(5x^2-2x^2)-(4x-5x)+(1-7)
=3X^2-(-X)+(-6)
=3X^2+X-6

Calculation: (4x ^ 4-6x ^ 2 + 2) (5x ^ 3-2x ^ 2 + x-1),

20X^7-8X^6-30X^5+12X^4+14X^3-4X^2-5X+2X^-1

The following determinant X-2 X-1 X-2 x-3 2x-2 2x-1 2x-2 2x-3 3x-3 3x-2 4x-5 3x-5 4x-3 5x-7 4x-3

x-2 x-1 x-2 x-3 2x-2 2x-1 2x-2 2x-3 3x-3 3x-2 4x-5 3x-5 4x 4x-3 5x-7 4x-3c1-c4,c2-c4,c3-c4 1 2 1 x-3 1 2 1 2x-3 2 3 x 3x-5 3 0 x-4 4x-3 r2-r1,r3-2r1,r4-3r11 2 1 x-3 0 0 0 x 0 -1 x-2 x+10 -6 x-7 x+3 r4...

2 x - 3 2x - 4 is 1 + 6 5x + 12

2 x - 3 2x - 4 is 1 + 6 5x + 12
Multiply both sides by 6
3x-2(2x-4)=6+5x+12
3x-4x+8=6+5x+12
6x=-10
x=-5/3
That is - 5 / 3

When x = 5, 2x-6() 8,5x + 2x() 8

When x = 5, 2x-6 () 8
Put x = 5 in,
2x-6=10-6=4
5x+2x=7x=35

Reduced fraction: 5x x2+x−6+2x−5 x2−x−12−7x−10 x2−6x+8

Original formula = 5x
(x+3)(x−2)+2x−5
(x+3)(x−4)-7x−10
(x−2)(x−4)
=5x(x−4)+(2x−5)(x−2)−(7x−10)(x+3)
(x+3)(x−2)(x−4)
=−40x+40
(x+3)(x−2)(x−4)．

0.1y=2x,5x+y=5

0.1y=2x
y=20x
Substituting 5x + y = 5
5x+20x=5
25x=5
therefore
x=0.2
y=20x=4