Decomposition factor 1. X ^ 4 + 4 2. X ^ 4 + y ^ 4 + (x + y) ^ 4 3. 4x ^ 2Y ^ 2-x ^ 4-y ^ 4-z ^ 4-2 (x ^ 2Y ^ 2-y ^ 2Z ^ 2-z ^ 2x * 2) speed ah

Decomposition factor 1. X ^ 4 + 4 2. X ^ 4 + y ^ 4 + (x + y) ^ 4 3. 4x ^ 2Y ^ 2-x ^ 4-y ^ 4-z ^ 4-2 (x ^ 2Y ^ 2-y ^ 2Z ^ 2-z ^ 2x * 2) speed ah

1.x^4+4 =x^4+4x^2+4-4x^2=(x^2+2)^2-(2x)^2=(x^2+2+2x)(x^2+2-2x)2.x^4+y^4+(x+y)^4=x^4+y^4+(x^2+y^2+2xy)^2=(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2=2[(x^2+y^2)^2+2xy(x^2+y^2)+（xy)^2]=2（x^2+...

Factorization of x-quartic-xsquare + 12x-36

X ^ 4-x ^ 2 + 12x-36 = x ^ 4 - (x ^ 2-12x + 36) = x ^ 4 - (X-6) ^ 2 = (x ^ 2 - (X-6)) (x ^ 2 + (X-6)) = (x ^ 2-x + 6) (x ^ 2 + X-6)

Decompose the following factors: complete square formula 1) x? + 12x + 36 1）x²+12x+36= 2）4x²-4x+1= 3）-2xy-x²-y²= 4）-x²+2xy-y²= 5)y²+y+1/4= 6）8y²-8y+2=

1）x²+12x+36=（x+6)²
2）4x²-4x+1=(2x-1)²
3）-2xy-x²-y²=-(x+y)²
4）-x²+2xy-y²=-(x-y)²
5)y²+y+1/4=(y+1/2)²
6）8y²-8y+2=2(2y-1)²

Factorization using complete square formula （1）y²-2y+1 （2）x²+2xy+y² （3）x²+8x+16 （4）4m²-12m+9 （5）25m²-1mn+n² （6）a²-6ab+9b²

（1）y²-2y+1 =（y-1）² （2）x²+2xy+y² =(x+y)²（3）x²+8x+16 =(x+4)²（4）4m²-12m+9=(2m+3)²（5）25m²-1mn+n²=(5m+n)² （6）a²-6ab+9b²=(...

How to calculate the square of X + 12x + 36, It doesn't count.

Multiply by cross
X 6
X 6
You see, the product of letters on the left is x ^ 2, and the product of numbers on the right is 36. After crossing and multiplying the left and right numbers and letters, the sum equals 12. In this way, cross multiplication is successful. Then write it horizontally as (x + 6) (x + 6). Cross multiplication is widely used in factorization. I hope you can learn it
I hope my answer will help you

Factorization factor: the square of x minus 2Y the square of Y minus 1

The square of x minus 2Y minus the square of Y minus 1
=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x+y+1)(x-y-1)

Factorization of (x + y) square + 2 (x + 1) + 2y-1 RT

(x+y)²+2(x+1)+2y-1
=(x+y)²+2x+2+2y-1
=(x+y)²+2x+2y+1
=(x+y)²+2(x+y)+1
=(x+y+1)²

Factorization: X squared (x-2y) y squared (2y-x)

Is there a + in the middle
x^2(x-2y)+y^2(2y-x)
=x^2(x-2y)-y^2(x-2y)
=(x^2-y^2)(x-2y)
=(x+y)(x-y)(x-2y)
What do not understand can continue to ask, at any time online

Decompose the following into factors: （1）2x2y-8y； （2）（x-y）2-2x+2y+1．

（1）2x2y-8y=2y（x2-4）
=2y（x+2）（x-2）．
（2）（x-y）2-2x+2y+1=（x-y）2-2（x-y）+1
=（x-y-1）2．

The complete square formula: 1 / 2 x 2 + 2 x y + 2 y 2 needs the process

1 / 2 x? + 2XY + 2Y
=1/2(x²+4xy+4y² )
=1/2(x+2y)²