f(x)=7x^7+6x^6+5x^5+4x^4+3x^3+2x^2+x I use Qin Jiushao algorithm to calculate. Why do I calculate 7108 and 21324 by calculator? Is there any problem with the order of operation? I've got (((((((7x + 6) x + 5) x + 4) x + 3) x + 2) x + 1) X Forgot to say x = 3

f(x)=7x^7+6x^6+5x^5+4x^4+3x^3+2x^2+x I use Qin Jiushao algorithm to calculate. Why do I calculate 7108 and 21324 by calculator? Is there any problem with the order of operation? I've got (((((((7x + 6) x + 5) x + 4) x + 3) x + 2) x + 1) X Forgot to say x = 3

f(x)=7x^7+6x^6+5x^5+4x^4+3x^3+2x^2+x
This is a function, not a fixed value. How can you calculate that?
7x ^ 7 + 6x ^ 6 + 5x ^ 5 + 4x ^ 4 + 3x ^ 3 + 2x ^ 2 + X and (((((((7x + 6) x + 5) x + 4) x + 3) x + 2) x + 1) x
It doesn't seem to be the same thing?

(1)-7x+2=2x-4(2)1-3/2=3x+5/2(3)4x-2=3-x(4)-7x+2=2x-4(5)-x=-2/5x+1(6)2x-1/3=-x/3+2

1. - 7x + 2 = 2x-42x + 7x = 4 + 29x = 6x = 2 / 32, 1-3 / 2 = 3x + 5 / 2-1 / 2 = 3x + 5 / 23x = - 3x = - 13, 4x-2 = 3-x4x + x = 3 + 25X = 5x = 14, repeat with question 1 5, - x = - 2 / 5x + 1x-2 / 5x = - 13 / 5 x = - 1x = - 5 / 36, 2x-1 / 3 = - X / 3 + 22x + X / 3 = 1 / 3 + 2x = 1

Factorization factor: (x2 + 3x + 2) (4x2 + 8x + 3) - 90

The original formula = (x + 1) (x + 2) (2x + 1) (2x + 3) - 90 = [(x + 1) (2x + 3)] [(x + 2) (2x + 1)] - 90 = (2x2 + 5x + 3) (2x2 + 5x + 2) - 90

The fourth power of (x + 1) (2x + 1) (3x-1) (4x-1) + Sixx, factorization

(x + 1) (2x + 1) (3x-1) (4x-1) (4x-1) + 6x ^ 4 = (x + 1) (3x-1) (2x + 1) (4x-1) (4x-1) + 6x ^ 4 = (3x ^ 2 + 2x-1) (8x ^ 2 + 2x-1) (8x ^ 2 + 2x-1) + 6x ^ 4 = (3x ^ 2 + 2x-1) (5x ^ 2 + 3x ^ 2 + 2x-1) + 6x ^ 4 = (3x ^ 2 + 2x-1) ^ 2 + 5x ^ 2 (3x ^ 2 + 2x-1) + 6x ^ 4 = (3x ^ 4 + 3x ^ 2 + 2x-1) + 6x ^ 4 = (3x ^ 4) (3x ^ 2 + 2x^ 2 + 2x-1 + 2x ^ 2) (3x ^ 2 + 2x-1 + 3x ^ 2) = (5x ^ 2 + 2x-1)

The value of the algebraic formula (2x + 1) (1-3x + 4x's Square) - x (3x-1) (3x + 1) + (the square of X + X + 1) (x-1) - (x-3) is independent of X Not (2x + 1) (the square of 1-3x + 4x) but (2x + 1) (the square of 1-2x + 4x)

(2x + 1) (1-3x + 4x squared) = (2x + 1) (1-2x + 4x squared-x) = 8x ^ 3 + 1-2x ^ 2-x
-x(3x-1)(3x+1)=-x(9x^2-1)=-9x^3+x
(x squared + X + 1) (x-1) = x ^ 3-1
-(x-3)=-x+3

Given that the value of the polynomial 3x2-4x + 6 is 9, then the polynomial x2 − 4 The value of 3x + 6 is () A. 7 B. 9 C. 12 D. 18

∵ the value of the polynomial 3x2-4x + 6 is 9,
∴3x2-4x=3，
∴x2−4
3x=1，
∴x2−4
3x+6=6+1=7．
Therefore, a

If the value of the algebraic expression 2x2 + 3x + 7 is 8, then the value of the algebraic expression 4x2 + 6x + 15 is () A. 2 B. 17 C. 3 D. 16

∵ the value of 2x2 + 3x + 7 is 8,
∴2x2+3x=1，
∴4x2+6x+15
=2（2x2+3x）+15
=2×1+15
=17．
Therefore, B

First, merge the similar terms, and then calculate the value of the algebraic expression - 3x + 2x-4x, where x = 1 / 5

-3x+2x-4x=-5x=-1/3

If the values of formula 4-3 (x + 2) and 4 (x-3) - 4 are equal, find the algebraic expression 2x ^ 3 + 4x-1 / 3x ^ 2 - (x + 3x ^ 2-2x ^ 3)

4-3(x+2)=4(x-3)-4
4-3x-6=4x-12-4
4x+3x=4-6+12+4
7x=14
X=2
2x^3+4x-1/3x^2-（x+3x^2-2x^3)
=2x^3+4x-1/3x^2-x-3x^2+2x^3
=4x^3-10/3x^2+3x
=4×8-(10/3)×4+3×2
=38/3

3x-7+4x=6x-22.x-1=5+2x 1.3x-7+4x=6x-2 2.x-1=5+2x

1、7X-7=6X-2
7X-6X=-2+7
X=5
2、X-2X=5+1
-X=6
X=-6