Equations: x-2y + 4Z = 0,2x + 3y-3z = 0... XYZ is not equal to 0, find (2x + Y-Z) \ (2x-y + Z)

Equations: x-2y + 4Z = 0,2x + 3y-3z = 0... XYZ is not equal to 0, find (2x + Y-Z) \ (2x-y + Z)

From 2x + 3y-3z = 0, Z-Y = 2x / 3
(2x+y-z)/(2x-y+z)
=(2x-（z-y）)/(2x+（z-y）)
Substituting Z-Y = 2x / 3 into the above formula, we can get:
(2x+y-z)/(2x-y+z)
=(2x-（2x/3）)/(2x+（2x/3）)
=（1-1/3）/（1+1/3）
=1/2
=0.5

(x+3y-4)(2x-y)

The original formula is equal to 2x ^ 2-xy + 6xy-3y ^ 2-8x + 4Y
=2x^2+5xy-3y^2-8x+4y

4 (2x + 3Y) ^ 2-9 (2x-3y) ^ 2 (X-Y) ^ 4 + X (X-Y) ^ 3-y (Y-X) ^ 3 1。 4(2x+3y)^2-9(2x-3y)^2 2。 (x-y)^4+x(x-y)^3-y(y-x)^3

4(2x+3y)^2-9(2x-3y)^2=【2（2x+3y）】2-【3（2x-3y）】2 =【2（2x+3y）+3（2x-3y）】【2（2x+3y）-3（2x-3y）】 =（4x+6y+6x-9y）（...

Some mathematical problems: known x.x + xy = 3, XY + y.y = - 2, find: (1) the value of x.x-y.y. (2) the value of x.x + 4xy + 3Y. Y (3) the value of 2x. X-xy-3y. Y

(1)xx+yy=3
-
xy+yy=-2
=
xx-yy=5
(2)xx+yy=3
+
3xy+3yy=-6
=
xx+4xy+3yy=-3
(3)2xx+2xy=6
-
3xy+3yy=-6
=
2xx-xy-3yy=0

Math problem (2x + 3Y + 2) (2x + 3y-2)

(2x+3y+2)(2x+3y-2)
=(2x+3y)²-4
=4x²+12xy+9y²-4
If you don't understand, I wish you a happy study!

On the mathematical problem of proportion: if x / 3Y = Y / (2x-5y) = (6x-15y) / x, find the value of (4x ^ 2-5xy + 6y ^ 2) / (x ^ 2-2xy + 3Y ^ 2) "/" is the fractional line, (...) is the denominator or or numerator, "x ^ 2" is the square of X One But it says x = - 2Y is wrong

X / 3Y = Y / (2x-5y) can deduce 2x ^ 2-5xy = 3Y ^ 2, (1) x / 3Y = (6x-15y) / X can deduce x ^ 2 = 18xy-45y ^ 2, (2) (1) × 15 + (2) 31x ^ 2-75xy = 18xyx ^ 2 = 3xy, that is, x = 3Y or x = 0

Given x-3y = 0, find the value of x square minus 2XY + y squared 2x + y times (X-Y)

x-3y=0
x=3y
The original formula = (2x + y) (X-Y) / (X-Y) 2
=(2x+y)/(x-y)
=(6y+y)/(3y-y)
=7y/2y
=7/2

Given x-3y = 0, find (2x + y) / (x ^ 2-2xy + y ^ 2) x (X-Y)

(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/（x-y）² *（x-y)=(2x+y)/（x-y）
x-3y=0,x=3y
(2x+y)/（x-y）=（6y+y）/（3y-y）=7/2

Given x-3y = 0, find the value of x ^ 2-2xy + y ^ 2 / 2x + y multiplication (X-Y)

x-3y=0,x=3y
X ^ 2-2xy + y ^ 2 / 2x + y multiply (X-Y)
=Multiply (y) by (y) - 2x / (2)
=(x-y)^3/(2x+y)
=(3y-y)^3/(6y+y)
=8y^2/7

Given x-3y = 0, find the value of (x ^ 2-2xy + y ^ 2 / 2x + y) × (X-Y)?

x-3y=0
x=3y
(x ^ 2-2xy + y ^ 2 of 2x + y) × (X-Y)
=(2x+y)/(x-y)^2*(x-y)
=(2x+y)/(x-y)
=(6y+y)/(3y-y)
=7y/2y
=7/2