2x^2y^3+(-3x^2y^3)-(-4x^2y^3)

2x^2y^3+(-3x^2y^3)-(-4x^2y^3)

Original formula = 2x ^ 2Y ^ 3-3x ^ 2Y ^ 3 + 4x ^ 2Y ^ 3
=3x²y³

Calculation: 2x ^ 2Y ^ 3 + (4x ^ 2Y ^ 3) - (- 3x ^ 2Y ^ 3)

2x^2y^3+(4x^2y^3)-(-3x^2y^3)
=x^2y^3[2+4-（-3）]
=9x^2y^3

The following equations are solved by substitution method: (1) x = 1-y 2x = - 1-3y (2) 4x-2y = 5 3x-4y = 15 (3) 2x = 5 (x + y) 3x-10 (x + y) = 2

x=1-y ①
2x=-1-3y ②
① It is concluded that: 1
2-2y=-1-3y
3y-2y=-1-2
∴y=-3
X=4
4x-2y=5 ①
3x-4y=15 ②
According to the results of (1)
4y=8x-10 ③
③ It is concluded that: 1
3x-8x+10=15
-5x=5
∴x=-1
y=-4.5
2x=5(x+y) ①
3x-10(x+y)=2 ②
According to the results of (1)
4x=10(x+y) ③
③ It is concluded that: 1
3x-4x=2
-x=2
∴x=-2
y=1.2

Solution 5x + 6y + 2Z = 80 4x-3y + Z = 16 3x-2y + 6Z = 92

5X+6Y+2Z=80------------①
4X-3Y+Z=16-------------②
3X-2Y+6Z=92------------③
① + 2 × 2
13X+4Z=112-------------④
① + 3 × 3
7X+10Z=178-------------⑤
5 × 4 - 2 × 5
65X-14X=560-256
51X=204
X=4
X = 4 into 4
Z = 15
X = 4, z = 15 into ①
Y = 5
X=4,Y=5,Z=15

Three elements one time: 3x-2y + Z = 3 ① 2x + Y-Z = 3 ② 4x + 3Y + 2Z = - 3 ③

3x-2y+z=3 ①
2x+y-z=3 ②
4x+3y+2z=-3 ③
(1) + 2
5x-y=6 (4)
(2) X 2 + (3)
8x+5y=3 (5)
(4) × 5 + (5)
33x=33
∴x=1
Substituting x = 1 into (4) yields
y=-1
Substituting x = 1, y = - 1 into (1) yields
z=-2
∴x=1
y=-1
z=-2

Solution equation: 2x + y + 3Z = 11,3x + 2y-2z = 11,4x-3y-2z = 4 (the process should be detailed)

2x+y+3z=11 ①
3x+2y-2z=11 ②
4x-3y-2z=4 ③
2*①-② x+8z=11
3*①+③ 10x+7z=37
X = 3, y = 1
Into equation 1
We get y = 2
X=3
Y=2
Z=1

Solving the system of three variable linear equations 2x + y + 3Z = 11 ① 3x + 2y-2z = 11 ② 4x-3y-2z = 4 ③

2x+y+3z=11 ①
3x+2y-2z=11 ②
4x-3y-2z=4 ③
2*①-② x+8z=11
3*①+③ 10x+7z=37
X = 3, y = 1
Into equation 1
We get y = 2
X=3
Y=2
Z=1

（1）x+y-z=0 2x-y+3z=2 x-4y-2z+6=0(2)3x+y=6 x+2y-z=5 5x-3y+2z=4(3)x+y+z=-1 4x-2y+3z=5 y-z=8-2x (4) 2X + 3Y = 53y-4z = 34z + 5x = 7 ternary linear equation, do not use scientific calculator to calculate cutting diagram,

The Gauss elimination method is often used to solve this kind of three variable linear equations, and the solutions of the four problems are the same
From x + Y-Z = 0, we can get z = x + y. by substituting into the remaining two equations, we can get: 2x-y + 3 (x + y) = 2, x-4y-2 (x + y) + 6 = 0, then we can get: 5x + 2Y = 2,
You can get 28y = 28, y = 1, and then x + 6y = 6 (or 5x + 2Y = 2 (or 5x + 2Y = 2) can get x = 0, and z = x + y = 1, z = x + y = 1, solved! Detailed process is like this, reference to do it, write so many, other three equations give the answer directly: (2) x = 2, y = 0, z = - 3; (3) x = 3, y = - 1, z = - 3; (3) x = 3, y = - 1, z = - 1, z = - 1, z = - 3; (3) x = 3, y = - 1, z = - 1, z = - 1, z = - 1, z = - 3, x = 3, x = 3, y = - 1, z = - 1, Z = - 3; (3) x- 3;
(4)x=5/3,y=5/9,z=-1/3;

Merge similar items: 5x + 3x = () 4x? + 2x? = () - 2A? B-3ba? = () - 9x? Y to the third power + 5x? + y to the third power = () Which are the same category? (1) 2XY and - 2XY (2) ABC and ab (3) 4AB and 0.25ab? 2 (4) 1 / 3x? Y and - 9yx? (5) 2x? Y and - 1 / 5xy? (6) 8 and 3

Merge similar items: 5x + 3x = (8x) 4x? + 2x? = (6x? - 2A? B-3ba? = (- 5A? 2b) - 9x? Y to the third power + 5x? Y to the third power = (- 4x? Y to the third power)
Which are the same category? (1) 2XY and - 2XY (2) ABC and ab (3) 4AB and 0.25ab? 2 (4) 1 / 3x? Y and - 9yx? (5) 2x? Y and - 1 / 5xy? (6) 8 and 3
Similar items are: (1) (4) (6)

The calculation of combined items of the same kind is 4x? - 5Y? - 5x + 3y-9-4y + 3 + X? + 5x, When a = 1 / 3, find the value of the polynomial 5A? - 5A + 4-3a? + 6a-5 (1) The value of a is directly substituted into the polynomial; (2) First, the polynomial is simplified, and then the value of a is substituted into the calculation

4x²-5y²-5x+3y-9-4y+3+x²+5x
=5x²-5y²-y-6