When x = radical 5-1, find the value of the third power of the algebraic formula x + the square of 2x + X

When x = radical 5-1, find the value of the third power of the algebraic formula x + the square of 2x + X

Because x ^ 3 + 2x ^ 2 + x = x (x ^ 2 + 2x + 1) = x (x + 1) ^ 2 = (√ 5-1) (√ 5-1 + 1) ^ 2 = (√ 5-1) * 5 = 5 √ 5-5

For the square of the algebraic expression x plus 2x minus 2, the value when x equals root 2 is? When x equals root 3 minus 1, the value is?

x^2+2x-2=(V2)^2+2V2-2 =2V2
x^2+2x-2=(x+1)^2-3=(V3-1+1)^2-3 = 3-3=0

Find the value of the square of the algebraic formula a minus the square of B when a is equal to two plus one and B is equal to three minus one When a is equal to the root 2 + 1 and B is equal to the root 3 - 1, the square of the algebraic formula a minus the square of B is obtained

2(√3+√2)-1

If x = root 3 plus 2 times root 2, y = 2 times root 2 minus 3, then the square of x minus 2XY plus the square of Y Help

X square + y square - 2XY = (X-Y) square
It's a formula
Look at the topic. You should learn
Do it yourself

The square of 9 (x-1) = (2x + 1) is solved by factorization Urgent

[3（x-1）]^2 -（2x+1）^2=0
[3（x-1）-(2x+1)][3（x-1）+( 2x+1)]=0
(x-4)(5x-2)=0
X = 4, or x = 2 / 5;

Using factorization to solve equation (main process) 3 (x-4) square = 2x-8 3 (x-4) square = 2x-8; (x-radical 3) square = 5 (radical 3-x); (x-1) (x + 3) = 12 Solution equation: (2x-1) square + 3 (2x-1) + 2 = 0

1、 3 (x-4) square = 2x-8 3 (x-4) ^ 2-2 (x-4) = 0 (x-4) [3 (x-4) - 2] = 0 (x-4) (3x-14) = 0 x = 4 x = 14 / 3, (x-radical 3) square = 5 (radical 3-x) (x-radical 3) [(x-radical 3) + 5] = 0 (x-radical 3) (x-radical 3 + 5) = 0 x = radical 3, x =

The square of X - 2x = 0 is done by factorization

x（x-2）=0
X = 0 or X-2 = 0
》X = 0 or x = 2

The square of 2x-1 is equal to 3-x square. How to solve it by factorization

(2x-1)^2=(3-x)^2
(2x-1)^2-(3-x)^2=0
[(2x-1)+(3-x)]*[(2x-1)-(3-x)]=0
(2x-1) + (3-x) = 0 or (2x-1) - (3-x) = 0
X = - 2 or x = 4 / 3

The square of (x-4) = (5-2x) is solved by factorization

(x-4) 2 = (5-2x) 2 (x-4) 2 - (5-2x) 2 = 0 (x-4 + 5-2x) (x-4-5 + 2x) = 0 (1-x) (3x-9) = 0 (1-x) * 3 * (x-3) = 03 (1-x) (x-3) = 01-x = 0 or x-3 = 0x = 1 or x = 3. I hope it will be helpful to you. If you have any questions, please follow up

Using factorization to solve the equation: (x-3) square = 2x (3-x)

(x-3)²=2x（3-x）
（3-x）²=2x（3-x）
（3-x-2x）（3-x）=0
（3-3x）（3-x）=0
x1=1,x2=3