Factorization: (2x + 5) (x ^ 2-9) (2x-7) - 91 use substitution method!

Factorization: (2x + 5) (x ^ 2-9) (2x-7) - 91 use substitution method!

(2x + 5) (x ^ 2-9) (2x-7) - 91 = (2x + 5) (x-3) (x + 3) (2x-7) - 91 = [(2x + 5) (x-3)] [(x + 3) (2x-7)] - 91 = (2x ^ 2-x-15) (2X ^ 2-x-21) - 91 let 2x ^ 2-x-15 = y, then the original formula = y (y-6) - 91 = y ^ 2-6y-91 = (y-13) (y + 7), so the original formula = (x ^ 2-x-15-13) (x ^

Factorization: 9 (2x + 3) ^ 2-4 (2x-5) ^ 2 = 0

9（2x+3)^2-4(2x-5)^2=0
[3（2x+3)]^2-[2(2x-5)]^2=0
(6x+9)^2-(4x-10)^2=0
[(6x+9)+(4x-10)][(6x+9)-(4x-10)]=0
(10x-1)(2x+19)=0
x=1/10,x=-19/2

Factorization (x-2x) ^ 2-7 (x ^ 2-2x) + 12 Please decompose the factor in the range of real numbers

The original formula = (x? - 2x-3) (x? - 2X-4)
=(x-3)(x+1)[(x-1)²-5]
=(x-3)(x+1)(x-1+√5)(x-1-√5)

Square factorization of square-9 (2x-y) of 4 (x + 2Y)

4(x+2y)^2-9(2x-y)^2
=[2(x+2y)-3(2x-y)][2(x+2y)+3(2x-y)]
=(-4x+7y)(8x+y)

Factorization: - 4 (x-2y) 2 + 9 (x + y) 2

-4（x-2y）2+9（x+y）2，
=[3（x+y）]2-[2（x-2y）]2，
=（3x+3y+2x-4y）（3x+3y-2x+4y），
=（5x-y）（x+7y）．

Factorization (2x + y) squared - (x + 2Y) squared Because I can't square it, so I wrote it

The square difference formula can be used:
m^2-n^2=(m+n)(m-n)
So (2x + y) ^ 2 - (x + 2Y) ^ 2
=（2x＋y+x+2y)(2x＋y-x-2y）
=(3x+3y)(x-y)
=3(x+y)(x-y)

Factorization: (2x + y) ^ 2 - (x + 2Y) ^ 2 (^ 2 stands for square)

(2x + y) ^ 2 - (x + 2Y) ^ 2 square difference formula
＝（2x+y+x+2y）（2x+y-x-2y）
=(3x+3y)(x-y)
=3(x+y)(x-y)

Factorization of 3 (x-2y) square-27 (2x + y) square

3(x-2y)²-27（2x+y）²
=3【(x-2y)²-9（2x+y）²】
In the use of square difference
=3【x-2y+3（2x+y）】【x-2y-3（2x+y）】
=3（7x+y）（ -5x-5y）
= -15（7x+y）（x+y）

Factorization: the square of (2x + y) - 6 (2x + y) + 9

Let a = 2x + y
Then the original formula = a 2 - 6A + 9
=(a-3)²
=(2x+y-3)²

Xsquare - 2x + 1 greater than or equal to 0

(x-1) ^ 2 is greater than or equal to 0
X is any real number