1.2x²-3=2.4x 6x=3-2x² √2(x²-1)=x(x-2)+1 x²-2(√5x-3)=1 1.2x²-3=2.4x 6x=3-2x² √2(x²-1)=x(x-2)+1 x²-2(√5x-3)=1 I hope there will be a concrete process for the first and second matching methods and the third and fourth formula method. I'm very grateful

1.2x²-3=2.4x 6x=3-2x² √2(x²-1)=x(x-2)+1 x²-2(√5x-3)=1 1.2x²-3=2.4x 6x=3-2x² √2(x²-1)=x(x-2)+1 x²-2(√5x-3)=1 I hope there will be a concrete process for the first and second matching methods and the third and fourth formula method. I'm very grateful

The equation is divided by 1.2x? - 2x = 5 / 2 Formula x? - 2x + 1 = 5 / 2 + 1 (x-1) 2 = 7 / 2, X-1 = ± √ (7 / 2) X-1 = ± (√ 14) / 2x-1 = (√ 14) / 2 or X-1 = - (√ 14) / 2x1 = (2 + √ 14) / 2, X2 = (...)

When solving the equation, it is not necessary to merge the same kind of terms is () a 2x = 3x B 2x + 1 = 0 C 6x-1 = 5 d 4x = 2 + 3x why B

Obviously, there are two items with X in a that need to be merged
There are two constant terms in C that need to be merged
Two items with X in d need to be merged
Only B doesn't need it

(5x + 2x-3-4x ^ 3) - (- x + 3x ^ 3-x ^ 2) merge similar items

(5x+2x-3-4x^3)-(-x+3x^3-x^2)
=5x+2x-3-4x^3+x-3x^3+x^2
=-7x^3+x^2+8x-3

Following the univariate first order equation (1) - merge the same kind term and the shift term (1) 5x-2x = 9; (2) x in 2 + 3x = 7 in 2

(1)5x-2x=9;
3x=9
X=3
(2)x/2+3x/2=7
2x=7
X=7/2

In the process of liberation, it is not necessary to merge the same kind of items: a.2x + 1 = 0, b.2x = 3x, C.6 - 1 = 5, d.4x = 2 + 3x

A can be calculated directly without merging

Given that the solution of equation 4x + 2m = 3x + 1 and equation 3x + 2m = 6x + 1 are the same, then M=______ .

From the first equation, x = 1-2m;
From the second equation, x = 2m-1
Three
From the meaning of the title: 1-2m = 2m-1
Three
The solution is: M = 1
2．
Therefore, fill in: 1
2．

It is known that the solutions of equation 4x + 2m = 3x + 1 and equation 3x + 2m = 6x + 1 are the same, (2) find the value of the algebraic expression (- 2m) ^ 2007 - (M-3 / 2) ^ 2008

4X + 2m = 3x + 1 x = 1-2m3x + 2m = 6x + 1 3x = (2m-1) / 3 the solutions of the two equations are the same, 1-2m = (2m-1) / 3 (4 / 3) (2m-1) = 0 2m-1 = 0 m = 1 / 2 (- 2m) ^ 2007 - (M-3 / 2) ^ 2008 = [(- 2) (1 / 2)] ^ 2007 - (1 / 2-3 / 2) ^ 2008 = (- 1) ^ 2007 - (- 1) ^ 2008 = - 1-1 = - 2

It is known that the solution of equation 4x + 2m = 3x + 1 and equation 3x + 2m = 6x + 1 on X are the same It is known that the solution of equation 4x + 2m = 3x + 1 and equation 3x + 2m = 6x + 1 on X are the same (1) Find the value of M (2) , calculate (- 4m + 2) 2012 power - (M-3 / 2) 2012 power Change (2), find (- 4m + 2) 2011 power - (M-3 / 2) 2010 power value

1. Find the solution of the two equations
X = 1-2m and x = (2m-1) / 3, the two solutions are the same, that is, 1-2m = (2m-1) / 3
M = 1 / 2
2. If the first term is 0 and the second term is 1, then 0-1 = - 1

It is known that the solution of the equation 4x + 2m = 3x + 1 on X is the same as that of the equation 3x + 2m = 6x + 1 on X. the algebraic expression (M-3 / 2) 2007 is obtained It is known that the solution of the equation 4x + 2m = 3x + 1 on X is the same as that of the equation 3x + 2m = 6x + 1 on X. the power of 2007 of the algebraic formula (M-3 / 2) is multiplied by the power of 2008 of (2m-2)

The solution of 4x + 2m = 3x + 1 is x = 1-2m,
The solution of 3x + 2m = 6x + 1 x = (2m-1) / 3
1-2m = (2m-1) / 3, M = 1 / 2
The 2007 power of (M-3 / 2) times the 2008 power of (2m-2) = (1 / 2-3 / 2) times the 2008 power of (2 * 1 / 2-2) = - 1 * 1 = - 1

Given the equation about X, 4x + 2m = 3x + 1 and 3x-8m = 5x + 6 have the same solution. Find the solution of M

4x+2m=3x+1
x=1-2m
3x-8m=5x+6
2x=-8m-6
x=-4m-3
So 1-2m = - 4m-3
2m=-4
m=-2