We know that X and y are opposite numbers in the solution of {2x-y = 4m + 3 2y-x = - 3, and find the value of M

We know that X and y are opposite numbers in the solution of {2x-y = 4m + 3 2y-x = - 3, and find the value of M

X and y are opposite numbers to each other
y=-x
So 2x + x = 4m + 3
-2x-x=-3
So - 3x = 3
x=-1
Then 2x + x = - 3 = 4m + 3
m=-3/2

Known equations 2x−y＝4m+3 The solution X and y of 2Y − x = − 3 are opposite numbers to each other, and the value of M is calculated

From the meaning of the title
2x−y＝4m+3
2y−x＝−3
x+y＝0 ，
(1) + 2
y＝−1
x＝1 ，
By substituting (1), M = 0

It is known that the solutions of the system of bivariate first-order equations {x + 2Y = 6m + 3,2x-y = 2m + 1} on X and y are opposite to each other, and the value of M is calculated

Equations
x＋2y＝6m＋3 ①
2x－y＝2m＋1 ②
It is known from the problem that the solutions of the equations are opposite to each other
Then, x + y = 0
Substituting into ①, we get
y＝6m＋3
By substituting the value of Y into (2), the
2x＝2m＋1＋6m＋3＝8m＋4
X = 4m + 2
X = 4m + 2, y = 6m + 3
Substituting x + y = 0, we get
10m＋5＝0
M = - 1 / 2
So, the value of M is - 1 / 2

The solution X and y of the system of bivariate linear equations 3x + 2Y = m + 3, 2x-y = 2m-1 are opposite numbers to each other, and the value of M is calculated

Because the solutions of the system of bivariate first-order equations about X and y are opposite to each other
So x = - Y
Substituting into equations
3（-y）+2y=m+3,2(-y)-y=2m-1
arrangement
-Y = m + 3 is equivalent to 3Y = - 3m-9
-3y=2m-1
United
M = - 10 come on

On the binary system of first order equations of X, y, 3x + 2Y = m + 3,2x-y = 2m-1, the solutions are opposite to each other, and the value of M is calculated

Because the solutions of the system of bivariate first-order equations about X and y are opposite to each other
So x = - Y
Substituting into equations
3（-y）+2y=m+3,2(-y)-y=2m-1
arrangement
-Y = m + 3 is equivalent to 3Y = - 3m-9
-3y=2m-1
United
M = - 10 come on

If the solutions of the system of bivariate linear equations 3x + 2Y = m + 3 (1) 2x-y = 2m-1 (2) are opposite to each other, find the value of M You say y = - x, can that be seen as x = - y

Because the two solutions of the system of equations are opposite to each other, we know that y = - X
There's nothing to say about this step. It's based on what's known
Replace it into the original equation system and change it into:
3x-2x=m+3,
2x+x=2m-1.
Namely:
③x=m+3
④3x=2m-1
(the idea of this step is very direct)
③ The results show that: 3x-3x = 3M + 9 - (2m-1),
(the idea of this step is: see that the coefficient of unknown number x in equation ④ is three times that of unknown number x in equation ③, so add subtract elimination method is used.)
That is: 0 = m + 10
Conclusion: M = - 10

It is known that the solution of the system of bivariate linear equations 2x + y = 6m (1) 3x-2y = 2m (2) satisfies the bivariate equation x / 3-y / 5 = 4

Use ① × 2 + ②
have to
（4x+2y)+(3x-2y)=12m+2m
7x =14m
So x = 2m
Then use ① × 3 - ② × 2
have to
(6x+3y)-(6x -4y)=18m-4m
7y=14m
So y = 2m
Substituting X / 3-y / 5 = 4
2 m / 3 - 2 m / 5 = 4
Multiply each item by 15
10m-6m=60
4m=60
m=15

We know that the cubic root sign X-2 + 2 = x, and the cubic root sign 3y-1 and the cubic root sign 1-2x are opposite numbers to each other

Cubic radical X-2 + 2 = x
=>x-2=(x-2)³
=>(x-2)[1-(x-2)²]=(x-2)(-x²+4x+5)=-(x-2)(x-5)(x+1)=0
=>x=-1,2,5
Cubic root 3y-1 and cubic root 1-2x are opposite numbers
=>3y-1=2x-1
=>y=(2/3)x
∴x=-1,y=-2/3
x=2,y=4/3
x=5,y=10/3

If y = under the root sign (2x-3) + under the root sign (3-2x) + 2, find the value of 2x + y

Greater than or equal to 0 under root sign
2x-3>=0,x>=3/2
3-2x>=0,x

Given that the third root Y-1 and the third root 1-2x are opposite numbers to each other, then Y / x = ()

The third root Y-1 and the third root 1-2x are opposite numbers to each other
Third root Y-1 + third root 1-2x = 0
y-1=2x-1
y/x=2