5x-3*(28-x)=12+2x

5x-3*(28-x)=12+2x

5x-84+3x=12+2x
5x+3x-2x=12+84
6x=96
x=16

Solve the following equations: (1) 2 / 5-3x = 3 / 3-5X; (2) 4 / x + 2-6 / 2x-3 = 1; (3) 12 / X-1 = 15 / 2x; (4) 5 / y + 17-4 / 3y-7 = - 2

（（1）2/5-3X=3/3-5X
Multiply both sides by 6
15-9X=6-10X
10X-9X=6-15
X=-9
(2)4/X+2-6/2x-3=1;
Double 12 on both sides
3X+6-4X+6=12
4X-3X=6+6-12
X=0
（3）12/X-1=15/2X
Double 60 on both sides
5X-5=8X
8X-5X=-5
3X=-5
X=-5/3
（4）5/Y+17-4/3Y-7=-2
Double 20 on both sides
4(Y+17)-5(3Y-7)=-40
4Y+68-15Y+35=-40
11Y=143
Y=143÷11
Y=13

Solving equations 1 (2x-3y = - 1y = 2x-1) 2 (2x + 5Y = 12 2x + 3Y = 6) 3 (3x-2y = 6 2x + 3Y = 17) 4 (5x + 2Y = 7 2x + y = 1) 

1: By substituting y = 2x-1 into 2x-3y = - 1, we can get: - 4x = - 4 then x = 1 2: by using 2x + 5Y = 12 to subtract 2x + 3Y = 6, y = 3, by substituting y = 3 into any form, x = - 3 / 2 3:3x-2y = 6 ① 2X + 3Y = 17 ② ① multiply by 2:6x-4y = 12 ③ ② multiply by 3:6x + 9y = 51, ④ - ③

Using substitution elimination method to solve the equations: {y = x + 1, 3x + 4Y = 11 {x-5y = 0, 3x + 2Y = 17 {5x-3y = - 1, 3x + y = 5 {2x-y + 5, 3x + 4Y = 2 {x + 3 / 1 = 2Y, 2 (x + 1) - y = 11 {x+y=9, 3(x+y)+2x=33

{2x-y+5,3x+4y=2
There are problems with the two expressions {x + 3 / 1 = 2Y, 2 (x + 1) - y = 11?
∵ replace y = x + 1 with 3x + 4Y = 11
The result is: 3x + 4 (x + 1) = 11
∴x=1 ∴y=2
∵x-5y=0,3x+2y=17
ν x = 5Y, replace it in the second equation
Results: 3 (5Y) + 2Y = 17
∴y=1 ∴x=5
∵5x-3y=-1,3x+y=5
∴Y=5-3x
5x-3 (5-3x) = - 1
∴x=1 ∴y=2
∵2x-y+5,3x+4y=2
∴Y=2x-5
The result is: 3x + 4 (2x-5) = 2
∴x=1 y=-3
∵x+y=9,3(x+y)+2x=33
∴Y=9-x
Results: 3 (x + 9-x) + 2x = 33
∴x=3 y=6

To solve the system of bivariate first order equations 3x-2y = 6,2x + 3Y = 17,2 parts x + y + 2 parts X-Y = 6,4 (x + y) - 5 (X-Y) = 2

The first x = 4, y = 3
The second one is a little unclear, x = 6, y = 8 / 9 (8 / 9)

Question 1: 8 (3x-1) - 9 (5x + 1) = 30 + 2 (2x-7) question 2: Y-1 of 2 = 3y-5 of 3-5 Question 3: 3 / 5 [5 / 3 (3x + 15) - 10] + 6 = 4 Steps of question 3

8（3X-1)-9(5X+1)=30+2(2X-7)
24X-8-45X-9=30+4X-14
-21X-17=4X+16
21X+4X=-17-16
25X=-33
X=-33/25
Y-1 in 2 = 3-5 in 3y-5
Multiply both sides by 10
5y-5=30-6y+10
6y+5y=30+10+5
11y=45
y=45/11
3 / 5 [5 / 3 (3x + 15) - 10] + 6 = 4
(3x+15)-10×3/5+6=4
3x+15-6+6=4
3x=4-15=-11
3x=-11/3

8x＋2x=100 3.5x＋17=25.4 3×8＋3x=48 2x-3.6=7.4 （2＋x）÷12.5=0.

So, 3.5x = 25.4-17, 3.5x = 8.4x = 2.43 × 8 + 3x = 48, so 3x = 48-3 * 8 = 24, x = 82x-3.6 = 7.4, so, 2x = 7.4 + 3.6 = 11, x = 5.5 (2 + x) △ 12.5 = 0.8, so 2 + x = 0.8 * 12.5 = 100x = 98

2X + 5 = 5x-7=

2X+5=5X-7
2X-5X=-7-5
-3X=-12
X=4
I hope I can help you. It's my honor to serve you

7x + 6 = 8-3x and 6-3 (x + 2 ＼ 3) = 2 ＼ 3 and 4x-3 (20-x) = 6x-7 (9-x) and 2x + 1 ＼ 3-5x-1 ＼ 6 = 1

7x+6=8-3x
7x+3x=8-6.
10x=2,
x=2/10.
x=1/5
6-3(x+2/3)=2/3,
6-3x-2=2/3.
3x=4-2/3,
=10/3.
x=10/9.
4x-3(20-x)=6x-7(9-x).
4x-3x-3*20=6x-7*9+7x.
13x-x=63-60.
12x=3,
x=1/4.
2x+1/3-5x-1/6=1.
-3x=1-1/3+1/6.
=5/6.
x=-5/18

13-2x=4,3x+4×0.5,5（x+4）=55,9÷1.5x=8,1.3x+x=13.8,x-0.7x=6.9,2x-8=1.4,1.8÷x=4 Find the formula of the solution of the equation,

13-2x=4
-2x=4-13
-2x=-9
x=4.5
3x+4*0.5=9.8
3x=9.8-2
3x=7.8
x=2.6
5(x+4)=55
x+4=11
x=11-4
X=7
9/(1.5x)=8
9=8*1.5x
12x=9
x=0.75
1.3x+x=13.8
2.3x=13.8
X=6
x-0.7x=6.9
0.3x=6.9
x=23
2x-8=1.4
2x=1.4+8
2x=9.4
x=4.7
1.8x=4
x=4/1.8
X = 20 of 9