It is known that one root of the equation 2x2-4x + 3Q = 0 on X is 1- 2, find its other root and the value of Q

Let the other root of the equation be X,
According to the relationship between root and coefficient,
Get 1-
2+x=2，
The solution is x = 1+
The other root is 1+
2．
Three more
2q=（1-
2）（1+
2）=-1，
The solution is q = - 2
3．

If the equation 2x in 3 minus 1 equals 2x in 4 + 1 and the equation 4x minus 1 in 2 equals 2 brackets x plus N, then find the square of n minus 3

∵﹙2x-1﹚/3=﹙2x+1)/4
∴x=7/2
∴4×7/2-1/2=2﹙7/2+n﹚
∴n=13/4
∴﹙n-3﹚²＝1/16

It is known that the equation (2x-a) / 3 - (2-A) / 2 = X-1 on X has the same solution as equation 3 (X-2) = 4x-5

Solution 3 (X-2) = 4x-5
3x-6=4x-5
x=-1
（2-a）/3-（2-a）/2=1-1
2(2-a)-3(2-a)=0
-(2-a)=0
A=2

We know the equation 2x − a with respect to X 3-x−a 2 = X-1 is the same as the solution of equation 3 (X-2) = 4x-5

(X-2) = 4x-5, 3x-6 = 4x-5, 3x-6 = 4x-5, 3x-4x = -5 + 5 + 6, - x = 1, x = -1,

What is the value of a, the solution of equation 2x + 5A = 0 on X is 3 larger than that of equation-3 / 4x-6 = 0?

2x+5a=0
x=-5a/2
-3/4x-6=0
3/4x=-6
x=-8
Then - 5A / 2 - (- 8) = 3
5a/2=8-3=5
A=2

Given that the equation of X 2x 2 + a (2x 2 + 4x + 3) = 2, the value of a is obtained according to the following conditions: (1) the two opposite numbers of the equation; (2) the two reciprocal equations of the equation (3) have and only one root is 0

The known equation of X is 2x ^ 2 + a (2x ^ 2 + 4x + 3 + 3) = 2, namely (2 + 2a) x ^ 2 + 4ax + 3a-2 = 0 △ ≥ 016a ^ 2-4 (2 + 2a) (3a-2) ≥ 016a ^ 2-4 (6a + 6A ^ 2-4-4-4a) ≥ 016a ^ 2-24a-24a-24a ^ 2 + 16 + 16A ≥ 08A ^ 2 + 8a-16 ≤ 0A ^ 2 + 2 + A-2 ≤ 0 (a + 2) (A-1) ≤ 0-2 ≤ a ≤ 1 according to Wei's theorem, get (1) x1x1x1x1x1 (1) x1x1x1 from the theorem, get the theorem (1) x1x1x1x1x1x1x1x1x1x1x1x1x11) from the theorem of the x 2 = -

The equation 3 [X-2 (x-a) for X is known 3) ] = 4x and 3x + a 12-1−5x 8 = 1 has the same solution. What is the solution?

From equation (1), x = 2
7A
From equation (2), x = 27 − 2A
Twenty-one
2
7a=27−2a
Twenty-one
A = 27
X = 27
28．
The solution is 27
28．

If the solution of the equation 2x-a = 0 on X is 2 larger than that of 4x + 7 = 3x + 8, find the value of A

By solving 4x + 7 = 3x + 8
x=1，
The solution of 2x-a = 0 is x = 3,
Substituting x = 3 into 2x-a = 0 gives a = 6

When m is the value, the solution of the equation 4x-2m = 3x-1 on X is twice that of x = 2x-3m

Solve the equation x = 2x-3m,
X = 3M,
By solving 4x-2m = 3x-1, x = 2m-1,
∵ the solution of the equation 4x-2m = 3x-1 for X is twice the solution for x = 2x-3m,
∴2×3m=2m-1，
The solution is: M = - 1
4．
A: when m = - 1
When 4, the solution of the equation 4x-2m = 3x-1 on X is twice the solution of x = 2x-3m

It is known that one root of the equation 2x2-4x + 3Q = 0 on X is 1- 2, find its other root and the value of Q