Given that the product of the quadratic trinomial expressions ax 2 + BX + 1 and 2x? - 3x + 1 does not contain the term of x 2 or the term of X, the coefficients a and B are obtained

Given that the product of the quadratic trinomial expressions ax 2 + BX + 1 and 2x? - 3x + 1 does not contain the term of x 2 or the term of X, the coefficients a and B are obtained

In the product of ax 2 + BX + 1 and 2x? - 3x + 1,
The coefficient of the term with x 2 = a-3b + 2 = 0
The coefficient of the term with x = B-3 = 0
b=3,a=7

It is known that the equation 2x2 + kx-1 = 0 (1) Proof: the equation has two unequal real roots; (2) If one root of the equation is - 1, find the other root and K value

It is proved that: (1) ? a = 2, B = k, C = - 1 ? Δ= k2-4 × 2 × (- 1) = K2 + 8, ∵ no matter what value k is, K2 ≥ 0, ᙽ K2 + 8 > 0, that is △ > 0, ? the equation 2x2 + kx-1 = 0 has two unequal real roots

1. Know: 6x-5x-3 = 0, find 12x - (6 + 10Y) =? 2. Know / 2x + 3 / + (x-3y) squared = 0 1. Know: 6x-5x-3 = 0, find: 12x - (6 + 10Y) =? 2. Know the square of / 2x + 3 / + (x-3y) = 0. Find: the square of X + y =? 3. Know: x + y = 6, xy = 2, find: 2 (x-xy) - (3xy-2y) =? 4. Knowing that the value of 9A + 8b-4 is 5, find: 6a-4 + 4B =? Try to answer within today

1. We know: 6x-5y-3 = 0, so 6x-5y = 3, so 12x - (6 + 10Y) = 2 (6x-5y) - 6 = 0
2. If we know | 2x + 3 | + (x-3y) ^ 2 = 0, then 2x + 3 = 0, and x-3y = 0, so x = - 3 / 2, y = - 1 / 2, we can get x ^ 2 + y = 9 / 4-1 / 2 = 7 / 4
3. 2 (x-xy) - (3xy-2y) reduction = 2 (x + y) - 5xy because x + y = 6, xy = 2
2 (x-xy) - (3xy-2y) reduction = 2 (x + y) - 5xy because x + y = 6xy = 2, then x + y = 2, xy = 1 / 3, the original formula = 4-5 / 3 = 7 / 3
4. Is the answer to the fourth question a number?

-How to solve 2x + 4 = - 3x?

-2x+4=-3x
3x-2x=-4
x=-4

Calculation: (1) (2x + 1) / 4 ＜ (15x-2) / 6 - (1 / 3) (6x + 4) (2) (2x-1.5) / 0.5 - (3x-0.6) / 0.2 > 0.19 （2）(2x-1.5)/0.5-(3x-0.6)/0.2＞(0.19-0.3x)/0.01

Can the title be sent more clearly

(6x^3-4x^2)/(-2x^2)-2(x+1)=________ (6x^3-4x^2)/(-2x^2)-2(x+1)=________

(6x^3-4x^2)/(-2x^2)-2(x+1)
=-3x+2-2x-2
=-5x

（1）x-2x-1/3=x-1/2 （2）3x+1/2 - 3x-2/10=2- 2x+3/5 （3） x+1/0.3 - 2x - 1/0.7=0 （4）2[4/3x-（2x/3 - 1/2）]=5/4x

1、 x-2x-1/3=x-1/2
x-2x-x=1/3-1/2
-2x=-1/6
x=1/12
2、3x+1/2 - 3x-2/10=2- 2x+3/5
3x-3x+2x=2+3/5-1/2+2/10
2x=23/10
x=23/20
3、x+1/0.3 - 2x - 1/0.7=0
x-2x=1/0.7-1/0.3
-x=10/7-10/3
-x=-40/21
x=40/21
4、2[4/3x-（2x/3 - 1/2）]=5/4x
Divide both sides by 2 at the same time
4/3x-（2x/3 - 1/2）=5x/8
4x/3-2x/3+1/2=5x/8
2x/3-5x/8=-1/2
Multiply by 24 at the same time
16x-15x=-12
x=-12

After simplification, X (x2-4) - (x + 3) (x2-3x + 2) - 2x (X-2) is evaluated, where x = 1.5

x（x2-4）-（x+3）（x2-3x+2）-2x（x-2）
=x3-4x-（x3-3x2+2x+3x2-9x+6）-2x2+4x
=x3-4x-x3+3x2-2x-3x2+9x-6-2x2+4x
=-2x2+7x-6
When x = 1.5, the original formula = - 2 × 1.52 + 7 × 1.5-6 = 6-6 = 0

If {3x ay = 16,2x + B on X and Y If {3x ay = 16,2x + by = 15 is {x = 7, y = 1. Then what is the solution of {3 (x + y) - A (X-Y) = 16,2 (x + y) + B (X-Y) = 15 about X and y? There is an answer to the equation of order of two variables~ emergency

The solution of a = 5B = 5B = 1 into 3 (x + y) - A (X-Y) = 16,2 (x + y) + B (b) (X-Y) = 16,2 (x + y) + B (X-Y) = 15 3 (x + y) - A (X-Y) = 16,2 (x + y) + B (X-Y) = 15 3 (x + y) - 5 (X-Y) = 162 (x + y) + (X-Y) = 15, simplify 4y-x = 8 (1) 3x + y = 15 (2) from (1) x = 4y-8 into (2) 12y-24 + y = 1513y = 39y = 39y = 3 = 3, y = 3, y = 3, y = 3, y = 3, y = 3, y = 3, y = 3, y = 3, y = 3

Math problem of grade 1: remove brackets and merge similar items: - (x ^ 2-2x) + (- 3x + 2x ^ 2)

Solution formula = one X ^ 2 + 2x-3x + 2x ^ 2
=- x ^ 2 + 2x ^ 2 + 2x-3x
=X ^ 2-x