(X & # 178; + x) &# 178; - 17 (X & # 178; + x) + 60 factorization

(X & # 178; + x) &# 178; - 17 (X & # 178; + x) + 60 factorization

（X²+X）²-17（X²+X）+60
=[(X²+X）-5][(X²+X）-12]
=(X²+X-5)(X+4）(x-3)
（17-X）²-X²=85
（17-X）²-X²=85
289-34x plus x-178; - x-178; = 85
289-34x=85
34x=204
X=6
The solution of X & # 178; - (17-x) &# 178; = 85 should be detailed!
X^2-289-X^2+34X=85
34X=374
X=11
(17-x) & 178; - X & 178; = 85 how to solve, mathematical experts help me!
There is also this question: the sum of the sides of the two squares is 17 cm, and the difference in area is 85 square cm. What are the areas of the two squares?
The sum of the sides of the two squares is 17 cm, and the area difference is 85 square cm. What are the areas of the two squares?
Use the square difference formula: (17-x + x) (17-x-x) = 85, that is, 17-2x = 5
X=6
That problem is this problem, and this equation is used to solve that problem
（17-X）²-X²=85
289-34X=85
34X=204
X=6
The areas are
(17-6) × (17-6) = 121 square centimeters
6 × 6 = 36 square centimeter, can you use the formula? I can't understand the equation... The equation is listed by yourself. I'm looking at other problems. In fact, I can't understand it. Er... It's better to use the equation to solve this problem. There's another problem: duckweed is an aquatic plant that grows very fast. Known to unfold
（17-X）²-X²=85
289-34X=85
34X=204
X=6
The areas are
(17-6) × (17-6) = 121 square centimeters
6 × 6 = 36 square centimeter? I can't understand the equation
-x^8-(-x²）^4+[-(-x)²·x²]²=
-x^8-(-x²）^4+[-(-x)²·x²]²
=-x^8-x^8+[-x^2·x²]²
=-x^8-x^8+[-x^4]²
=-x^8-x^8+ x^8
=-x^8
6²-x²=8,x=?
It should be 6x-x & # 178; = 8, x =?
x²-6x+8=0
The cross can be used by multiplication
(x-2)(x-4)=0
X = 2 or x = 4
x^2=24
x=±2√6
6x-x²=8
x²-6x+8=0
（x-2）（x-4）=0
x-2=0 x-4=0
x1=2 x2= 4
X^2=36-8=28
X = 2 root sign 7
6x-x & # 178; = 8 means X & # 178; - 6x + 8 = 0
（x-2)(x-4)=0
So x = 2 or x = 4
x²+2x-4y²+8y-3=
x²+2x-4y²+8y-3
=x²+2x+1-4y²+8y-4
=(x+1)²-4(y-1)²
=(x+1+2y-2)(x+1-2y+2)
=(x+2y-1)(x-2y+3)
What is the solution of the square of x-4x + 3 = 0?
analysis
Factorization method
(x-3)(x-1）=0
x1=3
x2=1
formula
x²-4x+3=0
(x-2)²-4+3=0
(x-2)²=1
x1=3
x2=1
x=3 x=1
x²-4x+3=0
（x-3)(x-1)=0
x1=3,x2=1
X & # 178; - 16 of 4-2-2 of X + x = x + 1 of 2
16/(x^2-4) +(2+x)/(x-2)=1/(x+2)
Multiply both sides by x ^ 2-4
16+(2+x)(x+2)=x-2
16+4+4x+x^2=x-2
x^2+3x+22=0
Because △ 0
So there is no solution
Are you asking for x?
If the value of polynomial 2Y ^ 2 + 3x is 1, then the value of polynomial 4Y ^ 2 + 6x-9 is?
The whole substitution method was used
4y^2+6x-9=2（2y^2+3x）-9=2*1-9=-7
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